Answer: choice A
f(x) = (1/4)x^2, f(x) = -0.5x^2, f(x) = x^2
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The coefficient in front of the x^2 term tells us how wide or narrow the parabola will be. It turns out that the further the coefficient value is from 0, in either direction, this will make the parabola more narrow.
Notice how 1/4 = 0.25 which is less than |-0.5| = 0.5 meaning that f(x) = (1/4)x^2 is wider than f(x) = -0.5x^2
Then comparing f(x) = -0.5x^2 to f(x) = 1x^2, we see that 0.5 is smaller than 1, so f(x) = -0.5x^2 is wider than f(x) = 1x^2
That is why the order from widest to narrowest is f(x) = (1/4)x^2, f(x) = -0.5x^2, f(x) = x^2
A graph shown below helps confirm the answer (note the color coding). In figure 1 is the graph of all three functions together. In figure 2, I reflect the second function help show the comparison of why it's the middle-most in terms of how wide it is (it is the orange parabola, which is the reflection of the red parabola)
Make 2/3 into 8/12 then subtract 1/12 and you get 7/12
Answer:
C. The charge of each minute of a call is $0.40
Step-by-step explanation:
We look at the point (1, 0.4)
We know that our x = 1 is 1 minute of the call.
We know that y = 0.4 is the cost when 1 minute of the call has elapsed.
Therefore, our answer is C.
Answer:
0.0597in/s
Step-by-step explanation:
The volume of the spherical balloon V= 4/3πr³
r is the radius of the balloon
The rate at which the volume is changing dV/dt is expressed as;\
dV/dt = dV/dr*dr/dt
dV/dr = 3(4/3πr²)
dV/dr = 4πr²
dV/dr = 4π(2)²
dV/dr = 16π
dV/dt = 3 in³/s
Substitute inti the formula
3 = 16πdr/dt
dr/dt = 3/16π
dr/dt = 3/50.24
dr/dt = 0.0597in/s
Hence the balloon is increasing at the rate of 0.0597in/s