Question

There are 5 slides, i've provided image for them all i need help with it. if your going to answer write it in order from slide 1-5 so it's easier to understand.

Answer 1

Answer:

mark as brainleast and fo-ll-ow me

Answer 2

Slide 1.

Part A.

1. Band A:  y = 600

2. Band B: y = 1.25x + 350

Part B.

200 students.

Slide 2.

Part A.

Fixed cost = $150

Rate per student served = $6

Part B.

To figure the cost/person, look at the change in cost divided by the change in attendance.

For 100 students, cost = $750.

For 150 students, cost = $1050.

Change in cost = $300

Change in students = 50

Cost per additional student = 300/50 = $6

Assuming the costs are linear, then the price charged for 100 students reflects the cost per student + a 'fixed cost' that applies to the order as a whole.

100 * 6 = $600, so the fixed cost is 750-600 = 150.

We can check this notion by substituting in the other equation.

Does 150*6 + 150 = 1050? Yes.

150*6=900

900+150 = 1050.

Slide 3.

Part A.

She can choose either band, with $9.75 per ticket, if 200 students attend

Part B.

Check the cost using band A and 200 people, including food

600 + 150 + (6*200) =

600 + 150 + 1200 = $1950

Cost per ticket: = 1950/200 = $9.75

Cost using band B, 200 people, including food:

350 + 1.25(200) + 150 + (6*200) =

350 + 250 + 150 + 1200 = $1950

Cost per ticket: 1950/200 = $9.75

This means that Paula can choose either band, and the ticket cost will be the same.

Slide 4.

Part A.

Cost per ticket: $8.50 (of Band A, since it is the cheaper one)

Part B.

Check the cost using band A and 300 people, including food

600 + 150 + (6*300) =

600 + 150 + 1800 = $2250

Cost per ticket: = 2250/300 = $8.50

Cost using band B, 200 people, including food:

350 + 1.25(300) + 150 + (6*300) =

350 + 375 + 150 + 1800 = $2675

Cost per ticket: 2675/300 ≈$8.92

Which means that in this scenario is Band A is less expensive.