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vladimir1956 [14]
3 years ago
11

PLEASE HELP GEOMETRY!!!

Mathematics
2 answers:
satela [25.4K]3 years ago
5 0
That would be A. The original xy coordinates are being moved to the left by three and up 5.
belka [17]3 years ago
3 0

Answer: A. (x,y)\rightarrow\ (x-3,y+5)

Step-by-step explanation:

We know that the coordinate notation of translation a point (x,y) by (a,b) is given by :-

(x,y)\rightarrow\ (x+a,y+b)

it also can be written as rule:  T_{a,b}(x, y)

Given statement :A triangle on a coordinate plane is translated according to the rule T_{-3,5}(x, y).

Then, the another way to write this rule will be:

(x,y)\rightarrow\ (x+(-3),y+(5))\\\\(x,y)\rightarrow\ (x-3,y+5)

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Questions Below. Would Appreciate Help!
kherson [118]

Answer:

The function that could be the function described is;

f(x) = -10 \cdot cos \left (\dfrac{2 \cdot \pi }{3} \cdot x \right ) + 10

Step-by-step explanation:

The given parameters of the cosine function are;

The period of the cosine function = 3

The maximum value of the cosine function = 20

The minimum value of the cosine function = 0

The general form of the cosine function is presented as follows;

y = A·cos(ω·x - ∅) + k

Where;

\left | A \right | = The amplitude = Constant

The period, T = 2·π/ω

The phase shift, = ∅/ω

k = The vertical translation = Constant

Therefore, by comparison, we have;

T = 3 = 2·π/ω

∴ ω = 2·π/3

The range of value of the cosine of an angle are;

-1 ≤ cos(θ) ≤ 1

Therefore, when A = 10, cos(ω·x - ∅) = 1 (maximum value of cos(θ)) and k = 10, we have;

y = A × cos(ω·x - ∅) + k

y = 10 × 1 + 10 = 20 = The maximum value of the function

Similarly, when A = 10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, we get;

y = 10 × -1 + 10 = 0 = The minimum value of the function

Given that the function is a reflection of the parent function, we can have;

A = -10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, to get;

y = -10 × -1 + 10 = 20 = The maximum value of the function

Similarly, for cos(ω·x - ∅) = 1 we get;

y = -10 × 1 + 10 = 0 = The minimum value of the function

Therefore, the likely values of the function are therefore;

A = -10, k = 10

The function is therefore presented as follows;

y = -10 × cos(2·π/3·x) + 10

8 0
3 years ago
Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!!!!!
Leni [432]

Answer:

At the time of launch height of the object was 60 meters.

Step-by-step explanation:

An object was launched from a platform and its height was modeled by the function,

h(x) = -5x² + 20x + 60

Where x = time or duration after the launch

At the time of launch, x = 0

So, by putting x = 0 in this equation,

h(0) = -5×(0) + 20×(0) + 60

h(0) = 60

Therefore, at the time of launch height of the object was 60 meters.

4 0
3 years ago
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