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joja [24]
3 years ago
13

Write an equation for a line passing through the points (-1, 8) and (0, 5).

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
3 0
Y=-3x+5


Mark brainliest please
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Help help please.....Thanks
Novosadov [1.4K]

Hey there! :)

Answer:

56.7 kg.

Step-by-step explanation:

Use the density formula to solve for the mass:

D = m/V.

Rearrange in terms of mass, or 'm':

DV = m.

Solve for the volume:

0.06 × 0.9 × 1.5 = 0.081 m³.

Plug this into the equation along with the density:

700 × 0.081 = 56.7 kg.

5 0
3 years ago
PLEASEEEE HELP ME WHAT IS THE SLOPE OF THE LINE AN Y INTERCEPT PLS HELP ME
nata0808 [166]
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8 0
3 years ago
Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 33% of all homeowners are ins
Lina20 [59]

Answer:

(a) The probability mass function of <em>X</em> is:

P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...

(b) The most likely value for <em>X</em> is 1.32.

(c) The probability that at least two of the four selected have earthquake insurance is 0.4015.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number among the four homeowners  who have earthquake insurance.

The probability that a homeowner has earthquake insurance is, <em>p</em> = 0.33.

The random sample of homeowners selected is, <em>n</em> = 4.

The event of a homeowner having an earthquake insurance is independent of the other three homeowners.

(a)

All the statements above clearly indicate that the random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 4 and <em>p</em> = 0.33.

The probability mass function of <em>X</em> is:

P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...

(b)

The most likely value of a random variable is the expected value.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.33\\=1.32

Thus, the most likely value for <em>X</em> is 1.32.

(c)

Compute the probability that at least two of the four selected have earthquake insurance as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{4\choose 0}\ (0.33)^{0}\ (1-0.33)^{4-0}-{4\choose 1}\ (0.33)^{1}\ (1-0.33)^{4-1}\\\\=1-0.20151121-0.39700716\\\\=0.40148163\\\\\approx 0.4015

Thus, the probability that at least two of the four selected have earthquake insurance is 0.4015.

3 0
3 years ago
Which of the following graphs the equation. <br> Y=1/3x -2
olga_2 [115]

Answer:

I don't know your answer options, but this is what the graph would look like:

**please mark brainliest!!

3 0
3 years ago
Which inequality is true?<br> 8/5 &lt;9/10 <br> 1&gt;6/5<br> 5/2&lt;2 1/2<br> 8/4&lt;5/2
AleksandrR [38]

Answer:

the last one : 8/4 < 5/2

Step-by-step explanation:

7 0
3 years ago
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