Y + 1 = -2x-3 in standard form *
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The given information are the coordinates of points H, Z and B. So, the first step to do is to plot these points on a Cartesian plane as shown in the attached picture. We can deduce visually that horse Z is closer to the barns than horse H. But, to further justify the answer, we have to provide the magnitude of the distance of horses H and Z to barn B. In this approach, we use the distance formula:
d = √(x₂ - x₁)² + (y₂ - y₁)²
Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = 19.4165
Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = 16.4012
Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters
Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.
d = √(x₂ - x₁)² + (y₂ - y₁)²
Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = 19.4165
Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = 16.4012
Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters
Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.
<h3>The distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft 6 inches.</h3>
Step-by-step explanation:
Here, the needed table is attached for the reference.
Now, as we can see from the table:
The distance covered by Cindy = 2 yards, 1 foot 3 inches
The distance covered by Tyrette = 7 feet, 2 inches
The distance covered by Nina = 2 yards, 1 foot, 1 inch
The distance covered by Monique = 7 feet, 4 inches
As we know : 1 yard = 3 feet
So, the distance covered by :
Cindy = 2 yards, 1 foot 3 inches = 3 ft x (2) + 1 ft + 3 in = 7 ft 3 in
Tyrette = 7 feet, 2 inches
Nina = 2 yards, 1 foot, 1 inch = = 3 ft x (2) + 1 ft + 1 in = 7 ft 1 in
Monique = 7 feet, 4 inches
So by comparing all distances, we can see that:
The maximum distances jumped by all four is 7 ft 4 inches.
The distance covered by Drew is less than 7 ft 7 in.
So, he must have jumped 7 ft 5 inches OR 7 ft 6 inches.
Hence, the distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft 6 inches.