6²÷2(3) +4
36/2(3)+4
=(18)(3)+4
=54+4
=58
Answer:
x = 12
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, then
The square of the tangent is equal to the product of the external part and the entire secant, that is
x² = 6(6 + 18) = 6 × 24 = 144 ( take the square root of both sides )
x =
= 12
Answer:
N = 18
Step-by-step explanation:
Rewrite the equations;
m+4n=8
m-n=-2
Eliminating m gives;
5n=10
n=2
Replacing for n in the first equation;
m+4(2)=8
m=8
Answer;
(0, 2)
Answer:
23
Step-by-step explanation:
