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olchik [2.2K]
3 years ago
13

What is the rule for the following geometric sequence? 64,128,256,512...

Mathematics
2 answers:
professor190 [17]3 years ago
8 0

Answer:

B

Step-by-step explanation:

The explicit rule for a geometric sequence is

a_{n} = a₁ (r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 64 and r = \frac{a_{2} }{a_{1} } = \frac{128}{64} = 2 , then

a_{n} = 64 (2)^{n-1} → B

antiseptic1488 [7]3 years ago
6 0

Answer:

b).

{ \tt{a _{n}  = a( {r}^{n - 1} )}} \\ { \tt{a _{n} = 64( {2}^{n - 1}) }}

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