The two cross sections shown are taken parallel to their respective bases. The cross sections have the same area. If the heights
1 answer:
Answer:
489.40 cm³
Step-by-step explanation:
Since the cross section is parallel to their respective bases, hence:
Area of the cylinder cross section = area of the circular base = πr²
where r is the radius of the cylinder base.
Area of other cross section = area of rectangle base = 3.8 cm * 8.1 cm
Since both cross sections have same area, hence:
Area of cylinder cross section = Area of rectangle base
πr² = 8.1 * 3.8
r² = 9.8
r = 3.1 cm
Volume of the cylinder = πr²h = π(3.1)²(15.9) = 489.40 cm³
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The probability that the numbers on both balls are odd numbers is
<em><u>Solution:</u></em>
<em><u>The probability of an event is given as:</u></em>
Given that, bowl contains 25 balls numbered 1 to 25
The sample space is given as;
{ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25 }
Therefore,
Total number of possible outcomes = 25
A ball is drawn and its number is noted. Without replacing the first ball, another ball is drawn.
Numbers on both balls are odd numbers
<em><u>Let us first find the probability that first ball is odd</u></em>
Favorable outcome = odd numbers
Favorable outcome = 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25
Number of favorable outcomes = 13
Thus, probability is given as:
Now Without replacing the first ball, another ball is drawn.
<em><u>Find the probability that second ball is odd number</u></em>
Without replacing means that ball is not put back into bowl
So, sample space = 25 - 1 = 24
Total number of possible outcomes = 25
Number of favorable outcomes = 13 - 1 = 12
Thus, probability is given as:
<em><u>Probability that the numbers on both balls are odd numbers is:</u></em>
Multiply both the probabilities
Thus, probability that the numbers on both balls are odd numbers is