Answer:
The point (3, 3) is not a solution of the first equation, therefore is not a solution of the given system of equations.
Step-by-step explanation:
How much candy at $1.16 a pound should be mixed with candy worth 86 cent a pound in order to obtain a mixture of 60 pounds of ca
1 answer:
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Hello,
x,y,z∈ IN
==>
x∈{35,36,37}
y∈{47,48,49}
z∈{141,144,147}
We must go futher:
if x=35 then y=4*35/3=46.666 not good , not whole
if x=36 then y=4*36/3=48 ok
if x=37 then y=37*4/3=49.333.. not good
So there is only one solution (36,48,144) for (x,y,z)
No problem with z for z=3/1*4/3*x=4x ==>whole.
x,y,z∈ IN
x∈{35,36,37}
y∈{47,48,49}
z∈{141,144,147}
We must go futher:
if x=35 then y=4*35/3=46.666 not good , not whole
if x=36 then y=4*36/3=48 ok
if x=37 then y=37*4/3=49.333.. not good
So there is only one solution (36,48,144) for (x,y,z)
No problem with z for z=3/1*4/3*x=4x ==>whole.