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Y_Kistochka [10]
3 years ago
7

Which situation can be modeled by the inequality 48−10x≥8?

Mathematics
2 answers:
salantis [7]3 years ago
7 0

Answer:

A. You have $48.00 to spend on socks, but you need to save at least $8.00 to pay for the bus trip home. You plan to spend the rest on socks at $10.00 each (including tax).

Step-by-step explanation:

kenny6666 [7]3 years ago
4 0

Answer:

A. You have $48 to spend on socks, but you need to save at least $8 to pay for the bus trip home. You plan to spend the rest on socks at $10 each (including tax).

Step-by-step explanation:

cause it's A

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The length of a rectangle is twice its width. The length is 4 1/2 feet. What is the area of the rectangle in square feet?
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Answer:

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Step-by-step explanation:

8 0
3 years ago
In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t
AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

         r = no. of success which is at least 5 in our case

         p = probability of success which is probability of Roman Catholic of

                 0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0
3 years ago
What is 83.34 written in expanded form?​
Vilka [71]

Answer:

80+3+0.3+0.04

Step-by-step explanation:

8 0
3 years ago
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What congruent postulate is needed for these triangles
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Answer:

i hope this helps you

Step-by-step explanation:

answer is c

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3 years ago
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We defined the operation of concatenation for sets of strings on p. 10, AB = { XY | X ∈ A and y ∈ B}Are the regular sets closed
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Answer and Explanation:

Solution: The operation of concatenation for a set of string on p. and the set is

     AB = {XY | X ∈ A and y ∈ B}.

We need to satisfy all these following properties to find out the standard set is closed under concatenation.

1- Union of two standard sets also belongs to the classic collection. For example, A and B are regular. AUB also belongs to a regular group.

2- Compliment of two standards set A and B are A’ and B’ also belonging to the standard set.

3- Intersection of two standards set A and B is A∩B is also a regular set member.

4- The difference between two regular sets is also standard. For example, the difference between A and B is A-B is also a standard set.

The closure of the regular set is also standard, and the concatenation of traditional sets is regular.

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4 years ago
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