15 ( 10 + y) = 3 i need help so bad

Q3) f(x) 2x^2 - 5x, g(x) = 3x^3 find g(4x)

mrs_skeptik [129]

Answer:

g(4x) = 192x^3

Step-by-step explanation:

For this problem, f(x) is irrelevant since we are simply are dealing with g(x). We will simply replace the value of x in g(x) with 4x. So let's do that.

g(x) = 3x^3

g(4x) = 3(4x)^3

g(4x) = 3(4^3)(x^3)

g(4x) = 3(64)(x^3)

g(4x) = 192x^3

Hence, g(4x) is 192x^3.

Cheers.

4 0

3 years ago

PLEASE HELPPP!! A box contains only black and white chips There are 8 black chips and 6 white chips How many white chips must be

Law Incorporation [45]

Lets take away 2 white chips...

8 black and 4 white...total of 12 chips
P(black) = 8/12 = 2/3

remove 2 white chips <==

3 0

3 years ago

How is the series 5+11+17…+251 represented in summation notation?

NISA [10]

Answer:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

Step-by-step explanation:

Given:

Series 5+11+17+...+251

To find:

Summation notation of the given series

Summation Notation:

$\displaystyle \large{\sum_{k=1}^n a_k}$

Where n is the number of terms and $\displaystyle \large{a_k}$ is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

Arithmetic Series

A series that has common difference.

Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

11-5 = 6
17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

Arithmetic Sequence

$\displaystyle \large{a_n=a_1+(n-1)d}$

Where $\displaystyle \large{a_n}$ is the nth term, $\displaystyle \large{a_1}$ is the first term and $\displaystyle \large{d}$ is the common difference:

So for our general term:

$\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}$

And for number of terms, substitute $\displaystyle \large{a_n}$ = 251 and solve for n:

$\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}$

Now we can convert the series to summation notation as given the formula above, substitute as we get:

$\displaystyle \large{\sum_{n=1}^{42}(6n-1)$

5 0

3 years ago

X-3= 0 and 4x+2y-1= 0

Assoli18 [71]

X-3=0
x=3

4x+2y-1=0
4(3)+2y-1=0
12+2y-1=0
11+2y=0
2y=-11
y=-5.5

3 0

3 years ago

Read 2 more answers

The angels of a triangle have a sum of 180°. The angles of a rectangle have a sum of 360°. The angels of a pentagon have a sum o

Airida [17]

Step-by-step explanation:

It is given that the angels of a triangle have a sum of 180°. The angles of a rectangle have a sum of 360°. The angels of a pentagon have a sum of 540.

Let me define the each terms.

1. We know that each angle in a triangle is 60°, So there is a three angle in a regular triangle.

60° + 60° + 60°
180°

2. We know that each angle in a rectangle, is 90°, So there is a four angle in a regular rectangle.

90° + 90°+90°+90°
360°

Similarly,

There is 8 angle in a regular octagon and each angle measurement is 135°.

So, sum of the angles of an octagon = 135° × 8

Sum of the angles of an octagon = 1080°

Therefore, the required sum of the angles of an octagon is 1080°

6 0

3 years ago