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Debora [2.8K]
3 years ago
8

How many real number solutions does the quadratic below have? y=2x^2-10x+6

Mathematics
2 answers:
Alexxx [7]3 years ago
7 0

Answer:

2 real number solutions.

Step-by-step explanation:

You check the value of the discriminant b^2 - 4ac.

Here it = (-10)^2 - 4*2* 6)

= 100 - 48

= 52. (Positive)

This means that it has 2 real number solutions.

If the discriminant = 0 it has one real number solution and if negative it has no real number solutions.

hodyreva [135]3 years ago
7 0

Answer:

i think its 2 real number

Step-by-step explanation:

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Step-by-step explanation:

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4.5

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3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

n= 955 represent the sampel size slected

x = 812 number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

The confidence interval for the proportion  would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 90% confidence interval the significance is \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution and we got.

z_{\alpha/2}=1.64

And replacing into the confidence interval formula we got:

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

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