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Alexus [3.1K]
3 years ago
8

Grade 5 module 2 lesson 25 problem set

Mathematics
1 answer:
Marizza181 [45]3 years ago
5 0
I dont see a question so i can’t answer
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Please help im so confused asap
enyata [817]

Answer:

624

Step-by-step explanation:

the area of the triangles:

12*10 = 120

120/2 = 60

since there are 2 triangles of the same dimensions that make up the surface area 60 + 60 = 120

area of the rectangles:

13*14 = 182

since there are 2 rectangles of the same dimensions 182 + 182 = 364

The last rectangular:

10*14 = 140

add all areas:

120 + 364 + 140 = 624

8 0
3 years ago
Read 2 more answers
If cos x= sin(20 + x)° and 0° < x < 90°, the value of xis
ruslelena [56]

Answer:

draw a right angle triangle

Step-by-step explanation:

Let one of the angles be A  

cos A = sin (90-A)  

90 - x - 20 = x  

2x = 70  

x = 35 degrees

4 0
3 years ago
Find the coordinates of the orthocenter of triangle ABC with vertices A (2, 0), B (2, 4), and C (6, 0).
ss7ja [257]

9514 1404 393

Answer:

  (2, 0)

Step-by-step explanation:

The orthocenter of a right triangle is the vertex where the right angle is located. Here, that is vertex A.

The orthocenter is (2, 0).

__

The orthocenter is the point where the altitudes intersect.

8 0
3 years ago
Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv
Natasha2012 [34]

Answer:

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=652.6 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size  

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=50-1=49

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

652.6-2.01\frac{311.7}{\sqrt{50}}=563.997    

652.6+2.01\frac{311.7}{\sqrt{50}}=741.203    

So on this case the 95% confidence interval would be given by (563.997;741.203)    

6 0
3 years ago
The formula for estimating the number, N, of a certain product sold is N = 8800ln(7t + 9), where t is the number of years after
arsen [322]
To determine or predict the expected number of sales after 2 years, we substitute 2 to the t of the givne equation.
                           N = (8800)xln(7(2) + 9)
                                N = 27,592.34
Thus, it is expected that the number of sales after 2 years is 27,592 units. 
6 0
3 years ago
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