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3 years ago

The sum of three consecutive terms x, y and z of an arithmetic progression is 45. If y=1/2(x+z), find the value of y.

Mathematics

1 answer:

Len [333]3 years ago

3 0

Answer:

y = 15

Step-by-step explanation:

x + y + z = 45 → (1)

Given

y = $\frac{1}{2}$ (x + z)

Multiply both sides by 2 to clear the fraction

2y = x + z ← substitute into (1)

2y + y = 45

3y = 45 ( divide both sides by 3 )

y = 15

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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The bottom right histogram is the correct one.

Step-by-step explanation:

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2 years ago

A child has 60 total coins. There are ten times as many nickels as there are quarters (q) and twelve more dimes than quarters. W

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3 years ago

A recent study of 26 city residents showed that the time they had lived at their present address has a mean of 10.3 years with t

svetlana [45]

Answer:

The 95% confidence interval is $9.15< \mu < 11.45$

Step-by-step explanation:

From the question we are told that

The sample size is n = 26

The mean is $\= x = 10.3$

The standard deviation is $s = 3$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * \frac{3}{\sqrt{26} }$

=> $E = 1.1532$

Generally 95% confidence interval is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $10.3 -1.1532 < \mu < 10.3 + 1.1532$

=> $9.15< \mu < 11.45$

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3 years ago

The sum of three consecutive terms x, y and z of an arithmetic progression is 45. If y=1/2(x+z), find the value of y.​

The sum of three consecutive terms x, y and z of an arithmetic progression is 45. If y=1/2(x+z), find the value of y.