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AVprozaik [17]
4 years ago
5

The sum of three consecutive terms x, y and z of an arithmetic progression is 45. If y=1/2(x+z), find the value of y.​

Mathematics
1 answer:
Len [333]4 years ago
3 0

Answer:

y = 15

Step-by-step explanation:

x + y + z = 45 → (1)

Given

y = \frac{1}{2}(x + z)

Multiply both sides by 2 to clear the fraction

2y = x + z ← substitute into (1)

2y + y = 45

3y = 45 ( divide both sides by 3 )

y = 15

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If s represents speed write an inequality to represent how fast a person can legally dive a vehicle in a school zone with a spee
ELEN [110]
The phrase “inequality” tells you that you will be using inequality signs, greater than, less than, greater than or equal to, or less than or equal to. Those signs look like this (not ordered) ≤ ≥ < >
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If you need help understanding why I used that particular inequality sign message me for help.
5 0
3 years ago
Hamburgers sell for 3 pounds for 6 dollars. if samantha buys 10 pounds for hamburgers how much will she pay
tamaranim1 [39]
You would start by 6÷3. This would tell you that for every proud of hamburger you pay $2.

Therefore multiply 10×2 and that equals 20.

Therefore, your answer is $20.
5 0
3 years ago
Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen
Jobisdone [24]

Parameterize S by the vector function

\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k

so that the normal vector to S is given by

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k

with magnitude

\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}

In this case, the normal vector is

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k

with magnitude \sqrt{1^2+2^2+1^2}=\sqrt6. The integral of f(x,y,z)=e^z over S is then

\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx

where T is the region in the x,y plane over which S is defined. In this case, it's the triangle in the plane z=0 which we can capture with 0\le x\le8 and 0\le y\le\frac{8-x}2, so that we have

\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}

5 0
3 years ago
I need help ASAP,, pleaseeee
jolli1 [7]

Answer:

1a) (-7,-3)

1b) (7,3)

1c) (3,-7)

3) 2 (180)

4) sorry I can't figure this one out

5) If it says 180° about the origin then it is (-5,10) if it isn't about the origin the say what it is in the comments and I will try to look at it again

Step-by-step explanation:

8 0
4 years ago
Help me with this question please, thank you !
Salsk061 [2.6K]

Answer:

2

Step-by-step explanation:

[(27divided by (-3)-9] divided by [15-21}

=[-9-9] divided by 3

= 6divided by 3 = 2

<h2><u><em>if answer is correct so mark me as brain lest :-)</em></u></h2>

<u><em></em></u>

5 0
2 years ago
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