Bonus #1) June 30 is equivalent to the 91st day of April or the 61st day of May.
Hilda's deposit of 4520 earned interest for 91-1 = 90 days.
Hilda's deposit of 580 earned interest for 61-10 = 51 days.
Hilda's deposit of 590 earned interest for 61-23 = 38 days.
Balance = $4520·(1 +.035/365)⁹⁰ + 580·(1 +.035/365)⁵¹ + 590·(1 +.035/365)³⁸
... = $4559.175 +582.843 +592.154
... ≈ $5734.17
Deposits total 4520 +580 +590 = 5690, so interest earned is
... $5734.17 -5690.00 = $44.17
Bonus #2) This problem can be worked the same way, except that withdrawals are subtracted from the final balance.
Owner's deposit of $12,300 earned interest for 91 days.
Owner's withdrawal of $3600 reduced the balance for 53 days.
Owner's withdrawal of $1200 reduced the balance for 10 days.
Balance = $12300·(1 +.035/365)⁹¹ -3600·(1 +.035/365)⁵³ -1200·(1 +.035/365)¹⁰
... = $12,407.795 -3618.342 -1201.151
... ≈ $7588.30
Interest earned = $7588.30 - (12300 -3600 -1200) = $88.30
Answer:
.753
Step-by-step explanation:
Let Ps = probability both marbles are the same color.
Let Pd = probability both marbles are a different color.
Pd = 1 -Ps
Let Pb = probability both marbles are blue
Let Pr = probability both marbles are red.
Let Pg = probability both marbles are green
Pb= 2/9 * 1/9 = 2/81
Pr= 4/9 * 3/9 = 12/81
Pg=.3/9 * 2/9= 6/81
Ps = Pb + Pr +Pg= 20/81
Pd =1-Ps= 61/81 = .753
Is this correct?
One son plays both, so subtract 1 from both categories. You're left with 1 son who plays both, 2 sons who play only football, and 1 son who plays only baseball. She has 4) 4 sons.
Answer: 57
Step-by-step explanation:
28 1/2 / 1/2
make 28 and 1/2 into 57/2
so now 57/2 divided by 1/2
the same as 57/2 times 2/1
multiply straight across
(57)(2)/(2)(1)
114/2
57
8+ the product of 2 and a number to the third power, what it means 2×m cubed. So it is 8+2m (cubed)
hope it helps
