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nirvana33 [79]
3 years ago
10

EEF or PEE SAUNA? (UNUS ANNUS-ERS ONLY)

Mathematics
2 answers:
Alina [70]3 years ago
7 0

Answer:

Eef (: of course.

Step-by-step explanation:

GRRR I miss unus annus!!!! What was your favorite video? My favorite video was either "Santa mukbang" ( PYRAMID OF NOG ),  "Exploring marks basement", or "Creating mark FISHbac"

Sophie [7]3 years ago
4 0
Eef. (dont make me miss unus annus again)
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iragen [17]
1/5( 5/2 x 4/7 -11/7) + 3/28

Multiply the terms (5/2 x 4/7) in bracket then subtract it from 11/14. Result will be 10/7.

Then multiply 1/5 with 10/7. The result will be 2/7.

2/7 + 3/28 = 11/28

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4 0
3 years ago
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Expand the expression <br><br><br> -7(k - 3)
Illusion [34]
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4 0
3 years ago
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0
3 years ago
What is and equation line that passes through the point (8,-5) and is parallel to the line 5x+4y=24
GenaCL600 [577]

Answer:

5x + 4x = 20

Step-by-step explanation:

You have your x and y values and if you substitute them in you find yourself with 40 - 20 = 24 this doesn't make sense. So you get another answer which can be set to 20 and 40 - 20 = 20 therefore you you can make sure that your line intersects with your x and y values.

4 0
3 years ago
Please help me: Ten athletes ran two races of the same length. The scatter plot shows their times. Identify each of these statem
Lemur [1.5K]

The scatter plot has been attached

Answer:

Options C, D & E are true

Step-by-step explanation:

Option A is wrong because from the scatter plot, only four athletes were faster in the second race than in the first one.

Option B is wrong because only 1 athlete had his second race time differing from the first race time by exactly 2 seconds.

Option C is true because exactly 9 of the times for the first race were at least 16 seconds

Option D is true because there are exactly 3 athletes who had the same time in both races

Option E is true because 8 of the times for the second race were less than 17 seconds

4 0
3 years ago
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