9(y - 4) + y + - 30 ????????????????

Can Someone Please Help Me With This Problem.

34kurt

Answer:

Option B {1,3,4,5}

Step-by-step explanation:

The domain of the function is nothing but the input of the given function

Therefore the domain of given function is

{1,3,4,5} Option B

5 0

2 years ago

Help! Simplify (see photo) pls explain If you don’t know pls don’t answer thanks

Temka [501]

Answer:

$-8 \sqrt{6}$

Step-by-step explanation:

$4i\sqrt{-24} \\4i\sqrt{-1} *\sqrt{24} \\4i*i*\sqrt{4}*\sqrt{6}\\-4 * 2*\sqrt{6} \\-8 \sqrt{6}$

.

$\sqrt{-1} =i \\i*i = -1$

7 0

3 years ago

What is 3 +3 divded by 4

Viefleur [7K]

Answer:3/2

Step-by-step explanation: 3+3/4

6/4=3/2

5 0

2 years ago

Read 2 more answers

guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d

Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)= $x^{2} y^{2} z^{2}$ =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)= $x^{2} y^{2} z^{2}$

$x^{2} +y^{2}+ z^{2}$ =1

=> $x^{2} +y^{2}+ z^{2}$ -1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)= $x^{2} y^{2} z^{2}$ and $x^{2} +y^{2}+ z^{2}$ -1=0

Differentiate

L(x)= $2xy^{2} z^{2}$ +2λx

L(y)= $2yx^{2} z^{2}$ +2λy

L(z)= $2zx^{2} y^{2}$ +2λz

L(λ)= $x^{2} +y^{2}+ z^{2}$ -1

Equating to 0

$2xy^{2} z^{2}$ +2λx =0

$2yx^{2} z^{2}$ +2λy = 0

$2zx^{2} y^{2}$ +2λz = 0

$x^{2} +y^{2}+ z^{2}$ -1 = 0

Factorize the above expressions

$2xy^{2} z^{2}$ +2λx =0

2x( $y^{2} z^{2}$ +λ)=0

2x=0 and ( $y^{2} z^{2}$ +λ)=0

x=0 and $y^{2} z^{2}$ = -λ

$2yx^{2} z^{2}$ +2λy = 0

2y( $x^{2} z^{2}$ +λ)=0

2y=0 and ( $x^{2} z^{2}$ +λ)=0

y=0 and $x^{2} z^{2}$ = -λ

$2zx^{2} y^{2}$ +2λz = 0

2z( $y^{2} x^{2}$ +λ)=0

2z=0 and ( $x^{2} y^{2}$ +λ)=0

z=0 and $x^{2} y^{2}$ = -λ

So we have ,

x=0 and $y^{2} z^{2}$ = -λ

y=0 and $x^{2} z^{2}$ = -λ

z=0 and $x^{2} y^{2}$ = -λ

The above expression becomes

x=y=z=0

This means that,

$x^{2} +y^{2}+ z^{2}$ =1

$x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1$

x= ±1/ $\sqrt{3}$

So,

y= ±1/ $\sqrt{3}$

z= ±1/ $\sqrt{3}$

The critic points are

x=y=z=±1/ $\sqrt{3}$

x=y=z=0

Therefore the maximum value of function f(x,y,z)= $x^{2} y^{2} z^{2}$ =1/27

And the minimum value is 0

To know more about function , visit

brainly.com/question/12426369

#SPJ4

3 0

1 year ago

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa

KengaRu [80]

Answer:

a. 0.5 or 50%

b. 0.496 or 49.6%

c. 0.8185 or 81.85%

d. Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm

e. 0.0252 or 2.52%

f. The qualifying speed would be 47.4 wpm.

Step-by-step explanation:

a. Let's find the z-score this way:

μ = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

p (z=0) = 0.5 or 50%

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

p (z = -0.01) = 0.496 or 49.6%

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

c.

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

In consequence,

p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

p = 0.0252 or 2.52%

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

The qualifying speed would be 47.4 wpm.

8 0

2 years ago