The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
5.5296
Step-by-step explanation:
to evaluate the expression 4x^4 y^3 we would substitute the value of x and y into it and evaluate. since x = 1/5 and y = 6
4x^4 y^3
4 × x^4 × 4× y³
4 × (1/5)∧4 × 4 × 6³
4× (0.2)∧4 × 4 × 216
4 × 0.0016 × 864
0.0064 × 864
5.5296
Step-by-step explanation:
The perfect square numbers between 100 and 200 are :
10^2 =100
11^2 =121
12^2 =144
13^2 =169
14^2 =196
Answer:
1. true
2. False
3. False
4. True
Step-by-step explanation:
