Hello,
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Answer B
(x^3-2^3=(x-2)(x²+2x+4)
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<u>ANSWER</u>
<u>EXPLANATION</u>
We have
.
Expressing in terms of means we should rewrite the relation such that will remain on one side of the equation while and any other constant will be at the other side.
To make the subject, we add to both sides of the equation.
.
we now multiply the whole equation by the reciprocal of the coefficient of , which is .
This implies that;
This simplifies to;
Answer:
give me brainliest
Given a line AB with Point C outside it.
Mark point D on the line AB. Join CD
With D as center, and any radius, draw an arc intersecting AB at E, and CD at F.
With C as center, and same radius as before, draw an arc intersecting CD at G.
Open a compass to length EF
Now,with G as center, and compass opened the same radius as before, draw an arc intersecting the previous arc at H.
Draw a line m passing through C and H.
Thus m is the line parallel to AB, and passing through point C
∴m∣∣AB
Step-by-step explanation:
Answer:
pretty sure the 1st choice and 3rd choice are correct not
Step-by-step explanation:
Since they are right triangles use Pythagorean Theorem.
a^2 + b^2 = c^2 where c is the hypotenuse.
a. 12^2 + b^2 = 13^2
144 + b^2 = 169
subtract 144 from both sides
b^2 = 25
take the square root of both sides
t = 5 This is also know as a Pythagorean Triple 5-12-13
b. a^2 + 9^2 = 12^2
a^2 + 81 = 144
subtract 81 from both sides
a^2 = 63
take the square root of both sides
a = √63
a = √(9 * 7)
a = 3√7
c. 6^2 + 9^2 = c^2
36 + 81 = c^2
117 = c^2
take the square root of each side
c = √117
c = √(9*13)
x = 3√13