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gizmo_the_mogwai [7]
3 years ago
13

The graph of a quadratic function is shown on the grid. which equation best represents the axis of symmetry

Mathematics
1 answer:
makkiz [27]3 years ago
7 0

Answer:

lkhf t gvjgjvhytcgh gvikyuhjinoli guvbkhjb

Step-by-step explanation:

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What is the value of x in the isosceles trapezoid below? 4x+37=9x
erma4kov [3.2K]

Answer:

X=11

Step-by-step explanation:

8 0
3 years ago
Dave buys a baseball catchers equipment for $295. The tax rate is 7.9%. How much tax did Dave pay? Round your answer to the near
Liono4ka [1.6K]

Answer:

23.31

Step-by-step explanation:

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3 years ago
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
3 years ago
How many solutions does the following equation have?<br> -2z+10+7z=16z+7
lorasvet [3.4K]

Start with

-2z+10+7z=16z+7

Simplify the left hand side by summing like terms (the one involving z):

5z+10 = 16z+7

Subtract 5z from both sides:

10 = 11z+7

Subtract 7 from both sides

3 = 11z

Divide both sides by 11:

z = \dfrac{3}{11}

7 0
3 years ago
Read 2 more answers
I don't get this at all please help
olchik [2.2K]
I think the answer is y=-2 because on the y-axis at -2, the line almost gets to that point but doesn't ever get to it
3 0
4 years ago
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