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densk [106]
3 years ago
6

What is the measurement of Q?

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
6 0

Answer: it would be 32

PilotLPTM [1.2K]3 years ago
4 0

Answer:

32

Step-by-step explanation:

I did the mathmathics

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Write an expression to find the perimeter of the rectangle below.
blondinia [14]

Answer:

18x^2

Step-by-step explanation:

6 0
2 years ago
Estimate 76.216+66.36 by first rounding each number to the nearest whole number.
xeze [42]

Answer:

142

Step-by-step explanation:

  • Round the numbers to their nearest WHOLE NUMBER.

76.216=76\\66.36=66

  • Then ADD

76+66=142

6 0
2 years ago
You need 250 mL of a 90% alcohol solution. On hand, you have a 75% alcohol mixture. How much of the 75% alcohol mixture and pure
stich3 [128]

9514 1404 393

Answer:

  • 100 mL of 75% solution
  • 150 mL of pure alcohol

Step-by-step explanation:

Let x represent the quantity (in mL) of pure alcohol needed for the mix. Then the amount of 75% needed is (250-x). The amount of alcohol in the mixture is ...

  1.00x +0.75(250 -x) = 0.90(250)

  0.25x +187.5 = 225 . . simplify

  0.25x = 37.5 . . . . . . . . subtract 187.5

  x = 150 . . . . . . . . . . . . . divide by 0.25

  (250 -x) = 100 . . . . mL of 75% solution

You need 100 mL of the 75% solution and 150 mL of pure alcohol to obtain the desired mixture.

8 0
3 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp
olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = \overline{x} = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data​ speeds i.e. x - \overline{x}

x - \overline{x} = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between​ carrier's highest data speed and the mean of all 50 data​ speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

\frac{59.98}{20.03}=2.99

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

z=\frac{x-\overline{x}}{s}

Using the given values, we get:

z=\frac{75.6-15.62}{20.03}=2.99

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly​ high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the  carrier's highest data speed​ is significantly higher.

3 0
3 years ago
cruising works three and a half hours every day and earns $12 per hour she works 5 days a week how much does Kevin earn in 4 wee
IRISSAK [1]
Kevin makes $840 in 4 weeks.

how much he makes per day $42
(3.5* 12= 42)

How much he makes per week
(42*5=210)
8 0
3 years ago
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