Solution :
Given :
Sample mean, 
Sample size, n = 129
Sample standard deviation, s = 8.2
a. Since the population standard deviation is unknown, therefore, we use the t-distribution.
b. Now for 95% confidence level,
α = 0.05, α/2 = 0.025
From the t tables, T.INV.2T(α, degree of freedom), we find the t value as
t =T.INV.2T(0.05, 128) = 2.34
Taking the positive value of t, we get
Confidence interval is ,
(32.52, 35.8)
95% confidence interval is (32.52, 35.8)
So with 
confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.
c. About of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about 
that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.
This would be random. This is because Carrie has no clue or has a limited knowledge of what type of shells he would grab.
Correct answer is the one you put
Answer:
41.67 kg
72 books
Step-by-step explanation:
mass of 150 books = 150/108 × 30 kg
= 41.67 kg
number of books = 20/30 × 108 books
= 72 books
Step-by-step explanation:
Use midpoint formula ,
x = 12 , y = 4
midpoint of line segment is (12,4)
