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aleksandr82 [10.1K]
2 years ago
12

Question 9

Mathematics
1 answer:
timurjin [86]2 years ago
8 0

Answer:

<u>The</u><u> </u><u>requ</u><u>ired</u><u> </u><u>num</u><u>ber</u><u> is</u><u> </u><u>7</u><u>0</u><u>.</u>

Step-by-step explanation:

let the no. be 10y + x where x is unit digit and y is ten's digit.

given , sum of the digit is 7

x + y = 7 ...(1)

also , reversing the no. we get 10x + y ,where x is ten's digit and y is unit digit.

given reversed digit decreases the number by 63 .

so, 10y + x - ( 10x + y ) = 63

9y -9x = 63

( dividing both side by 9 )

y - x = 7 ....(2)

adding 1 and 2 [ refer attachment ]

so the required original number is

10y + x = 10×7+0 = 70

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