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aleksandr82 [10.1K]
2 years ago
12

Question 9

Mathematics
1 answer:
timurjin [86]2 years ago
8 0

Answer:

<u>The</u><u> </u><u>requ</u><u>ired</u><u> </u><u>num</u><u>ber</u><u> is</u><u> </u><u>7</u><u>0</u><u>.</u>

Step-by-step explanation:

let the no. be 10y + x where x is unit digit and y is ten's digit.

given , sum of the digit is 7

x + y = 7 ...(1)

also , reversing the no. we get 10x + y ,where x is ten's digit and y is unit digit.

given reversed digit decreases the number by 63 .

so, 10y + x - ( 10x + y ) = 63

9y -9x = 63

( dividing both side by 9 )

y - x = 7 ....(2)

adding 1 and 2 [ refer attachment ]

so the required original number is

10y + x = 10×7+0 = 70

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I. Daska is situated at a distance of 15 miles from both Gujranwala and Sialkot. A bus travels from Gujranwala to Daska at an av
son4ous [18]

Answer:

The average speed of the entire trip is 8.5 miles per hour.

Step-by-step explanation:

Speed = Total  Distance / Total Time

So we have to find the total distance and the total time taken .

1) From Gujranwala to Daska

speed= 25miles/hour           distance = 15miles

Time taken = distance / speed

                   = 15/25= 0.6 hours

2)  From Daska to Sialkot

speed= 40miles/hour           distance = 15miles

Time taken = distance / speed

                   = 40/15= 2.67 hours

3 ) From  Sialkot to Daska

speed= 30miles/hour           distance = 15miles

Time taken = distance / speed

                   = 30/15= 2 hours

The total distance traveled to three places is = 15+ 15+15= 45miles

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Speed= 45/ 5.3

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The average speed of the entire trip is 8.5 miles per hour.

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3 years ago
Tickets to a show cost $5.50 for adults and $4.25 for students. A family is purchasing 2 adult tickets and 3 student tickets. Wh
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Answer:

F = $11,421.90

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Complete question;

You purchased a vehicle for $32,000. It's value will depreciate at a rate of 18.62%. What will it's value be in 5 years, when you finally have it paid off

Step-by-step explanation:

Given;

Initial value P = $32,000

Depreciation rate r = 18.62% = 0.1862

Time t = 5

Final value = F

Using the compound depreciation formula;

F = P(1 - r)^t

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F = $32,000(1 - 0.1862)^5

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The outside temperature can be estimated based on how fast crickets chirp. At 104 chirps per minute, the temperature is 63 degre
Rasek [7]

Answer:

For 124 chirps per minute the temperature is 68 ºF.

For 68 chirps per minute the temperature is 54 ºF.

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form

f(x)=b+mx

b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.

m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.

We know that

  • At 104 chirps per minute, the temperature is 63 ºF.
  • At 176 chirps per minute, the temperature is 81 ºF.

This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and  y = the temperature in ºF.

To find a linear function that let us find the outside temperature from how fast crickets chirp we must:

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m=\frac{y_2-y_1}{x_2-x_1}=\frac{81-63}{176-104}=\frac{1}{4}

  • Find the equation:

81=\frac{1}{4}\cdot 104+b

Solving for b

b=81-\frac{1}{4} (176)=37

Therefore, the linear function is

y=\frac{1}{4} \cdot x+37

Now, using this linear function we can know the temperature when we know the chirps per minute:

For 124 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (124)+37=68

For 68 chirps per minute the temperature is:

y=\frac{1}{4} \cdot (68)+37=54

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