Answer:
I think it is (x^2+9) x (x-1) x (x+1)
Step-by-step explanation:
(not sure if right but had a go)
Answer:
Step-by-step explanation:
we know that
The general equation of a quadratic function in factored form is equal to
where
a is a coefficient of the leading term
x_1 and x_2 are the roots
we have
substitute
Applying the distributive property convert to expanded form
therefore
Answer:
a). 0.294
b) 0.11
Step-by-step explanation:
From the given information:
the probability of the low risk = 0.60
the probability of the high risk = 0.40
let represent no claim
let represent 1 claim
let represent 2 claim :
For low risk;
so, = (0.80 * 0.60 = 0.48), = (0.15* 0.60=0.09), = (0.05 * 0.60=0.03)
For high risk:
= (0.50 * 0.40 = 0.2), = (0.30 * 0.40 = 0.12) , = ( 0.20 * 0.40 = 0.08)
Therefore:
a), the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:
b) What is the probability that a randomly selected policyholder filed two claims?
the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08
= 0.11
It should be 2 to 3, so the last answer should be right
Answer:
Bridget's first fish =f = 5 ounces
Bridget's dad first fish weighs 17 ounces
Step-by-step explanation:
Solution:
Bridget's fishes:
f ounces
2f ounces
3f+2 ounces
1/2f ounces
3/5f ounces
Total= f +2f + (3f+2) + 1/2f +3/5f
=3f + 3f + 2 + 5f+6f/10
=6f + 2 + 11f/10
=60f+11f/10 +2
=71/10f +2
Bridget's dad fishes
3f+2
4/5f
2f+4
1/2f
Total =(3f+2) + (2f+4) + 4/5f +1/2f
=3f+2+2f+4 + 8f+5f/10
=5f + 6 + 13/10f
= 50f+13f/10 + 6
=63/10f +6
Equate the total weight
71/10f +2=63/10f +6
Collect like terms
71/10f - 63/10f =6-2
71f-63f/10 = 4
8f/10=4
Cross product
8f=40
Divide both sides by 8
f=5
Bridget's first fish =f = 5 ounces
Bridget's dad first fish = 3f +2
=3(5)+2
=15+2
=17 ounces
Bridget's dad first fish weighs 17 ounces