The area of a sector is 339.336 cm²
The area of a sector is defined to be as the region of space bounded by a boundary from the center of the circle.
It can be determined by using the formula:
Given that;
- Radius r = 18 cm
- Angle θ = 120°
Then. the area of the sector can be calculated as:
A = 339.336 cm²
Learn more about the area of a sector here:
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Since the triangle is an equilateral triangle we know all of it's sides must be the same length, with that in mind the angles that make up the triangle must be equal as well. Knowing that a triangle's three interior angles make up 180 degrees we know that the size of each angle must be one third of this (as each angle must be equal).
180/3 = 60
then we may split the triangle along it's altitude into two special right triangles
more specifically two 30-60-90 triangles.
this means that the side with 30 degrees will be some value "x" where the side for 60 degrees will be related as it is "x*sqrt(3)" and the hypotenuse (which would be the side of the triangle) would be proportionally "2x"
this would mean that the altitude is the side associated with the 60 degree angle as such we can solve for "x" using this.
12= x*sqrt(3)
12/sqrt(3)=x
4sqrt(3)=x (simplifying the radical we get "x" equals 4 square root 3)
now we may solve for the side length of the triangle which is "2x"
2*4sqrt(3) -> 8sqrt (3)
eight square root of three is the answer.
The answer is 12 including both sides and angles.
When you cut a square piece of paper from one point to the opposite point it should make two triangles.
Thus each triangle has 3 sides and 3 angles so two triangles has 6 angles and 6 sides
So 12, sides and angles added together.
Answer:
√36 = 6
a^2 + b^2 = c^2
6^2 + 6^2 = c^2
36 + 36 = c^2
72 = c^2
√72 = c
2 36
2 18
2 9
3 3
6√2 = c
6√2 = (estimate rounded up, 8.49)
