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3 years ago

What are the domain and range of the function f(x)=x^4-2x^2-4?

Mathematics

1 answer:

BigorU [14]3 years ago

8 0

Answer:

The domain is Al real numbers and the range is -5

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Can you guys please help me

m_a_m_a [10]

The answer is B. First turn all the results from the spelling competition into fractions (or ratios).
Megan: 45/50 = 9/10
Justin: 27/30 = 9/10
Fernando: 84/120 = 7/10
Then, use this information to find which answer is correct.
Have a nice day! :)

4 0

3 years ago

What is the explicit formula for this geometric sequence?

victus00 [196]

Answer:

The explicit formula for this geometric sequence is 27.3(n-1)

4 0

3 years ago

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

The 1.8 million cars use $1.85 \times 10^{10}$ liters each year

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

Hence, the number of liters used is $1.85 \times 10^{10}$

Read more about distance and rates at:

brainly.com/question/24659604

4 0

3 years ago

In a survey of 100 people, 10 preferred onions on their hot dogs. What percent preferred onions?

Aleks [24]

1/10 if you divide 10 by 100 it would be 1/10

4 0

3 years ago

What's equivalent to 4b

Nostrana [21]

Answer:

4 x 5

Step-by-step explanation:

6 0

3 years ago