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noname [10]
3 years ago
10

Sara packed 7 boxes of books. Each box had 13 mystery books and 15 science fiction books. How many more science fiction books th

an mystery books did Sara pack?
Mathematics
1 answer:
Mrrafil [7]3 years ago
5 0

Answer:

There are 14 more science fiction books than mystery books

Step-by-step explanation:

Multiply 13 x 7 = 91

Multiply 15 x 7 = 105

Subtract 105 - 91 = 14

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Elenna [48]
The value of y = 40.

5x = 40
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180 = 40 + 40 + (2y + 20)
  40 = y
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Tim's company offers a reimbursement package of $0.65 per mile plus $145
zalisa [80]

Answer:

C = 0.65x + 145

Step-by-step explanation:

Assume:

Number of miles = x

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Total reimbursement = C = $0.65*x + $145 = $0.65x + $145

4 0
3 years ago
Consider a home mortgage of ​$225,000 at a fixed APR of 4.5 ​% for 30 years. a. Calculate the monthly payment. b. Determine the
White raven [17]

<u>The formula for the monthly payment</u>.....

M= \frac{P(1+r)^nr}{[(1+r)^n] -1} , where P = the principal amount, r = the monthly interest rate and n = the total number of months.

Here annual interest rate is given as 4.5%

So, the monthly interest rate =\frac{4.5\%}{12}= 0.375\% = 0.00375

Total number of months = (30*12)months=360 months

Also given that, the principal amount is $225000

a.  So, the monthly payment will be.....

M= \frac{P(1+r)^nr}{[(1+r)^n] -1}\\ \\ M= \frac{225000(1+0.00375)^3^6^0*0.00375}{(1+0.00375)^3^6^0 -1}\\ \\ M= \frac{225000(1.00375)^3^6^0*0.00375}{(1.00375)^3^6^0 -1} \\ \\ M \approx 1140

Thus, the monthly payment will be approximately $1140


b. The <u>total amount paid</u> over the term of the loan will be: \$ 1140*360 months = \$ 410400


c.   As the principal amount was $225000 , so the amount of interest = (\$ 410400- \$ 225000)= \$ 185400

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and the percentage of amount that is paid toward the interest =\frac{185400}{410400}*100\%=45.18\%

4 0
3 years ago
Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 &lt; = x &lt; = 8. The length of the curve is . (Type an exact an
Mashutka [201]

Answer:

\sqrt\frac{387}{20}

Step-by-step explanation:

Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx

y=\dfrac{3}{5}x^{\frac{5}{3}}-  \dfrac{3}{4}x^{\frac{1}{3}}+6

\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}

1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})

=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}

For the Interval 1\leq x\leq 8

Length of the Curve =\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\

Using T1-Calculator

=\sqrt\frac{387}{20}

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3 years ago
Someone plz help meee
coldgirl [10]

Answer:

The second one

Step-by-step explanation:

7 0
3 years ago
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