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Nana76 [90]
3 years ago
13

Are 4/5 and 1/2 equivalents?

Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

Not the same!

Step-by-step explanation:

4/5 is 0.8 and 1/2 is 0.5 so they aren't similar

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I need help fast pleasee
trapecia [35]

Answer:

<em>y = - cos ( </em>\frac{3}{4}<em> x + </em>\frac{\pi }{4}<em> ) </em>

Step-by-step explanation:

y = A cos ( Bx + C) + D

Vertical shift D = 0

A = - 1

Compression / Stretching B

Period of given function is \frac{8\pi }{3}

Period of cos x is 2π

\frac{8\pi }{3} = \frac{2\pi }{B} ⇒ B = \frac{3}{4}

Horizontal shift is C ÷ B

Horizontal shift of given function is \frac{\pi }{3}

\frac{\pi }{3} = C ÷ \frac{3}{4} ⇒ C = \frac{\pi }{4}

So, the equation of given function is

<em>y = - cos ( </em>\frac{3}{4}<em> x + </em>\frac{\pi }{4}<em> ) </em>

4 0
2 years ago
What does x and y =??????
Kazeer [188]

Answer:

x=30. y=60

Step-by-step explanation:

DG is a straight segment so it sums to 180 degrees. ECG is a right angle so 90 degrees. The rest is described as 2x and x. So 3x=90 degrees. x=30. Eh is also a straight segment. since we know x, we know that ECD is 60 degrees. So y+y=120 degrees. 2y=120. y=60.

6 0
3 years ago
Pls help me!!! ( pls dont answer if you don’t have the answer I will report you ...).
bezimeni [28]
I think 517.26
I did 10 times 3^2 (9) it equals 90. Then 90 times 3.14 and got 282.74. Then did 800- 282.74 and got 517.26
5 0
3 years ago
Read 2 more answers
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
3 years ago
Pleaseee helpppp!!!!! I keep getting this answer wrong on the test :(
zaharov [31]
Next time study more! I know its hard but you can do it keep trying ur best :)
5 0
3 years ago
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