1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
monitta
3 years ago
9

I need help with b and jk

Mathematics
1 answer:
arlik [135]3 years ago
5 0

Answer:

b = 1

JK = 3

Step-by-step explanation:

5b - 2 = 9b - 6

4b = 4

b = 1

JK = 3

You might be interested in
Using laws of exponents, explain how to simplify (x-2)3.
Allushta [10]

Answer:

The answer would be 3x-6

Step-by-step explanation:

3 times x equals 3x. 3 times -2 equals -6. So it would be 3x-6

5 0
3 years ago
Identify an equation in point-slope form for the line perpendicular to y = -1/2x + 11 that passes through (4, -8)
andrey2020 [161]

Answer:

y+8 = 2(x-4)

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. Since we know the slope of the first line is -1/2, this means the slope of the line perpendicular to it is 2.

And since we know the coordinated located on the line, we can fill out the formula for poiny-slope form:

y-y1 = m(x-x1)

6 0
3 years ago
32 is 25% of x. Hurry please
kondor19780726 [428]
The answer is 128

hope that helps!
3 0
3 years ago
Read 2 more answers
I’m order to solve the following system of equations by addition which of the following could you do before adding the equations
Over [174]

Answer:

Unclear

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
show that thw roots of the equation (x-a)(x_b)=k^2 are always real if a,b and k are real. Please I really need help with this
VLD [36.1K]

Answer:

see explanation

Step-by-step explanation:

Check the value of the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real

• If b² - 4ac = 0 roots are real and equal

• If b² - 4ac < 0 then roots are not real

given (x - a)(x - b) = k² ( expand factors )

x² - bx - ax - k² = 0 ( in standard form )

x² + x(- a - b) - k² = 0

with a = 1, b = (- a - b), c = -k²

b² - 4ac = (- a - b)² + 4k²

For a, b, k ∈ R then (- a - b)² ≥ 0 and 4k² ≥ 0

Hence roots of the equation are always real for a, b, k ∈ R


           

8 0
3 years ago
Other questions:
  • Please help thanks so much 20 points.
    10·1 answer
  • the perimeter of a regular hexagon is represented by this expression 42x-24. the expression ______ represents the length of one
    8·2 answers
  • Which graph represents the equation x=-2
    7·2 answers
  • Karen has a bag of 18 white beads, 3 red beads, and 3 pink beads. Which color spinner could be used to simulate pulling a bead o
    6·2 answers
  • What is the logical conclusion, based upon the information given in the
    14·1 answer
  • Please Help! Dimitri bought a cylindrical clay flowerpot that holds approximately 15 gallons of dry soil (1 gallon ≈ 0.15 cubic
    12·1 answer
  • Am I'm correct I linked a picture with it​
    5·2 answers
  • Simplify the expression.<br> 3.7-4.6n-3n + 6
    14·1 answer
  • QUICK PLEASE HELP ME ANSWER THESE QUESTIONS AND SHOW WORK!!!<br> I WILL MARK BRAINLIEST!!!
    14·2 answers
  • Function g is defined by g(x)=3(x+8) what is the value of g(12)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!