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3 years ago

I need help with b and jk

Mathematics

1 answer:

arlik [135]3 years ago

5 0

Answer:

b = 1

JK = 3

Step-by-step explanation:

5b - 2 = 9b - 6

4b = 4

b = 1

JK = 3

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Help...please?? Thanks guys

vfiekz [6]

Answer:

x=20

Step-by-step explanation:

The Pythagorean theorem is

a^2 +b^2 = c^2

where a and b are the legs and c is the hypotenuse.

The legs are x and 15 and the hypotenuse is 25

x^2 + 15^2 = 25^2

x^2 +225 = 625

Subtract 225 from each side

x^2 +225-225 = 625-225

x^2 = 400

Take the square root of each side

sqrt(x^2) = sqrt(400)

x = 20

4 0

3 years ago

Read 2 more answers

The measure of arc BCD is

makkiz [27]

Answer:

m∠BCD = 140°

Step-by-step explanation:

ABCD is cyclic quadrilateral. A property of cyclic quadrilateral states that the opposite angles of it sum up to 180°. Here:

m∠A + m∠C =180° and m∠B + m∠D = 180°

So, m∠A + m∠C =180°

m∠A = 40° (given in the question)

40° + m∠C = 180°

m∠C = 180° - 40° = 140°

∴m∠C = m∠BCD = 140°

6 0

3 years ago

Graph the linear equation

baherus [9]

For the equation
.. x - y = 4
you can divide by 4 to put the equation into intercept form. This form shows you both interecepts at once.
.. x/4 +y/(-4) = 1

The x-intercept is (4, 0).
The y-intercept is (0, -4).

The graph is shown below.

7 0

3 years ago

Evaluate each expression for the given value (please answer all)

Anna [14]

Answer:

-20a - 65 = -104 for a = 2.7

-6x + 52 = 45 for x = 1 1/6

Step-by-step explanation:

-20a - 50 for a = 2.7

Insert 2.7 in for a.

-20(2.7) - 50 = -54 - 50 = -104

-6x + 52 for x = 1 1/6

Insert 1 1/6 for x.

-6(1 1/6) + 52 = -7 + 52 = 45

8 0

3 years ago

Please help! I attached the question below.

kompoz [17]

Answer:

$\frac{2(c+2)}{c(c-2)}$

Step-by-step explanation:

$\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }$

Identity used:

$a^{2}-b^{2}=(a-b)(a+b)$

$\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }$

Now let us divide the modified expressions:

$\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})}$ ÷ $\frac{(c-2)^2}{2(6c^{3}+15c^{2}) }$

we get:

$\frac{2(c+2)}{c(c-2)}$

5 0

3 years ago