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FromTheMoon [43]
3 years ago
6

Bradley bought 2 cakes for his class Valentines's party. There are 23 students in his class. How much cake will each student rec

eive?
Mathematics
1 answer:
Cloud [144]3 years ago
4 0
So 2 divded into 23 parts =2/23 which is simplest form

so each person will recieve 2/23 of a cake
You might be interested in
Task: Nonpermissible Values for Rational Expressions [30 points] Write a rational expression that has the nonpermissible values
igor_vitrenko [27]

Answer:

A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

Step-by-step explanation:

A rational expression has a nonpermissible value when for a given value of x, the denominator is equal to zero. In addition, we assume that both numerator and denominator are represented by polynomials, such that:

f(x) = \frac{p(x)}{q(x)} (1)

Then, the factorized form of q(x) must be:

q(x) = x\cdot (x-17) (2)

If we know that p(x) = 4, then the rational expression is:

f(x) = \frac{4}{x\cdot (x-17)} (3)

A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

8 0
3 years ago
How do I rewrite the improper fractions as a mixture number? Please explain step by step to get marked as brainliest
Liula [17]

Answer:

1) Divide the numerator by the denominator.

2) Write down the whole number result.

3) Use the remainder as the new numerator over the denominator. This is the fraction part of the mixed number.

Step-by-step explanation:

not sure of this will help... but hope it does!

3 0
3 years ago
Read 2 more answers
Thanks for helping <br> can you show the steps
Vikki [24]
Can you tell me what they are asking you to do
This is so I know if you understand the question
7 0
2 years ago
I NEED HELP!!! PLZ HELP!!!!!!!!!
Digiron [165]

Answer:

30.06

Step-by-step explanation:

The question states WHAT DID THEY PAY BEFORE INSTALATION CHARGES.

So 30.06$

588.34-555.28=30.06

3 0
3 years ago
Don't get this
kap26 [50]
I'll talk you through it so you can see why it's true, and then
you can set up the 2-column proof on your own:

Look at the two pointy triangles, hanging down like moth-wings
on each side of 'OC'.

-- Their long sides are equal,  OA = OB, because both of those lines
are radii of the big circle.

-- Their short sides are equal, OC = OC, because they're both the same line.

-- The angle between their long side and short side ... the two angles up at 'O',
are equal, because OC is the bisector of the whole angle there.

-- So now you have what I think you call 'SAS' ... two sides and the included angle of one triangle equal to two sides and the included angle of another triangle.
(When I was in high school geometry, this was not called 'SAS' ... the alphabet
did not extend as far as 'S' yet, and we had to call this congruence theorem
"broken arrow".)

These triangles are not congruent the way they are now, because one is
the mirror image of the other one.  But if you folded the paper along 'OC',
or if you cut one triangle out and turn it over, it would exactly lie on top of
the other one, and they would be congruent.

So their angles at 'A' and at 'B' are also equal ... those are the angles that
you need to prove equal.
5 0
3 years ago
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