<span>C. whoever comes into the house</span>
Let the number of songs Lou has = X
Kelly has 4 times as many as Lou, which would be written as 4X
Tiffany has 6 times as many songs as Lou, which would be written as 6X
The total number of songs = 682
You need to add all three people together to equal 682
So you would get:
X + 4X + 6X = 682 songs.
Combine all like terms ( 6x + 4x + X = 11x)
11x = 682
Now to solve for X divide both sides by 11:
x = 682 / 11 = 62
Lou = x = 62 songs.
Kelly = 4x = 4(62) = 4*62 = 248 songs.
Tiffany = 6x = 6(62) = 6 *62 = 372 songs.
Answer:
9
Step-by-step explanation:
One did 10,one did 9, and 1 did 8 and 9 is the median number of those 3 numbers.
Explanation:
Marginal distribution: This distribution gives the probability for each possible value of the Random variable ignoring other random variables. Basically, the values of other variables is not considered in the marginal distribution, they can be any value possible. For example, if you have two variables X and Y, the probability of X being equal to a value, lets say, 4, contemplates every possible scenario where X is equal to 4, independently of the value Y has taken. If you want the probability of a dice being a multiple of 3, you are interested that the dice is either 3 or 6, but you dont care if the dice is even or odd.
Conditional distribution: This distribution contrasts from the previous one in the sense that we are restricting the universe of events to specific condition for other variable, making a modification of our marginal results. If we know that throwing a dice will give us a result higher than 2, then to in order to calculate the probability of the dice being a multiple of 3 using that condition, we have two favourable cases (3 and 6) from 4 total possible results (3,4,5 and 6) discarding the impossible values (1 and 2) from this universe since they dont match the condition given (note that the restrictions given can also reduce the total of favourable cases).
The joint distribution calculates the probabilities for two different events (related to two different random variables) occuring simultaneously. If we want to calculate the joint probability of a dice being multiple of 3 and greater than 2 at the same time, our possible cases in this case are 3 and 6 from 6 possible results. We are not discarding 1 or 2 as possible results because we are not assuming, that the dice is greater than 2, that is another condition that we should met in the combination of events.
Okay! Assuming this only wants the tax that will be added to the total, multiply the decimal percent by the cost of the item.
7.5% = .075
14.80 * .075 = 1.11
1.11 of tax will be added onto the total cost.
The total cost would be 15.91, which you can get from adding 14.80 to 1.11 or by doing 14.80 * 1.075. Regardless, the answer to this question is 1.11.
