Question

Write a program to display the following diamond-shape like pattern based on the height given by the user. Assume that the user will always enter a positive odd number.

Answer 1

Answer:

try:

   size = int(input("Enter a number: "))

except ValueError:

   print("must be a number")

if size==0:

   print("number must be greater than zero.")

elif size%2==0:

   print("number must be odd.")

   

else:

   obj = '#'

   mid_size = round(size/2)

   s = size - mid_size

   count = 2

   counts = 1

   for i in range(size+1):

       if i<=mid_size:

           print(" " *(size - i) + (obj+" ") * i)

       elif i>mid_size:

           print(" " * (s + counts) + (obj + " ") * (i - count))

           count += 2

           counts += 1

Explanation:

The python source code uses a try and except statement to check for value error and print a diamond shape of the object "#" determined by the input number.