Simplify the expresion 12. 12g + 9g

Fill in the correct formula called a contains numbers from Rhodes 1 to 20 you can use the formula blank to find the volume of th

Flauer [41]

Answer:

Waist

Explanation:

5 0

3 years ago

Write a C++ program to count even and odd numbers in array. The array size is 50. The array elements will be entered by the user

vlabodo [156]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

int numbers[50];

int evekount = 0, odkount = 0;

for(int i = 0; i<50;i++){

cin>>numbers[i];

if(numbers[i]%2==0){ evekount++; }

else{ odkount++; }

}

cout<<"Even Count: "<<evekount<<endl;

cout<<"Odd Count: "<<odkount<<endl;

return 0;

}

Explanation:

This declares the integer array of number

int numbers[50];

This initializes the even count and odd count to 0

int evekount = 0, odkount = 0;

This iterates from 1 to 50

for(int i = 0; i<50;i++){

This gets input for the array

cin>>numbers[i];

This checks for even

if(numbers[i]%2==0){ evekount++; }

This checks for odd

else{ odkount++; }

}

This prints the even count

cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

cout<<"Odd Count: "<<odkount<<endl;

3 0

3 years ago

g The reciprocal Fibonacci constant ψ is defined by the infinite sum: ψ=∑n=1 [infinity] 1 Fn Where Fn are the Fibonacci numbers

timama [110]

Answer:

see explaination

Explanation:

MATLAB script:

% MATLAB script that calculates reciprocal Fibonacci constant Ψ

% Initial Values

a0 = 1;

a1 = 1;

% Looping variable

i = 2;

% Reading n value from user

n = input(' Enter n value: ');

% Initializing sum

sum = (1/a0) + (1/a1);

% Loop till i reaches n value

while i <= n

% Finding term in Fibnocii series

a2 = a0 + a1;

% Accumulating Sum

sum = sum + (1/a2);

% Updating previous terms

a0 = a1;

a1 = a2;

% Incrementing loop variable

i = i + 1;

endwhile

% Printing result

printf("\n Reciprocol Fibnocii Constant: %f \n", sum);

See attachment for sample output

5 0

3 years ago

Develop a program that will calculate the area and perimeter of a rectangle. The length and width can be given as constant.(LENG

o-na [289]

Answer:

#include <iostream>

using namespace std;

int main()

{

int length = 8;

int width = 8;

int perimeter = 2*(length + width);

int area = length * width;

cout<<"The perimeter is "<<perimeter<<endl;

cout<<"The area is "<<area<<endl;

return 0;

}

Explanation:

include the library iostream for using the input/output instructions in the c++ programming.

Create the main function and define the variable length and width with values.

Then, use the formula for calculating the perimeter and area of rectangle.

$perimeter = 2*(length + width)$

$area = length * width$

and store in the variables and finally print the output.

8 0

3 years ago

The information security organization performs a significant role in the implementation of solutions that mitigate risk and cont

sergiy2304 [10]

Answer:

Subject matter experts

Explanation:

Because the security organization institutes the procedures and policies to be executed, they occupy the role of Subject matter expert.

A subject matter expert is a person with a thorough and deep knowledge of a particular process, function, technology, machine, material or type of equipment. Such a person is an expert on that subject.

Therefore the information security organization occupies the role of Subject matter expert.

6 0

4 years ago

Simplify the expresion12. 12g + 9g​

Simplify the expresion12. 12g + 9g