Answer:
The factors of x² - 3·x - 18, are;
(x - 6), (x + 3)
Step-by-step explanation:
The given quadratic expression is presented as follows;
x² - 3·x - 18
To factorize the given expression, we look for two numbers, which are the constant terms in the factors, such that the sum of the numbers is -3, while the product of the numbers is -18
By examination, we have the numbers -6, and 3, which gives;
-6 + 3 = -3
-6 × 3 = -18
Therefore, we can write;
x² - 3·x - 18 = (x - 6) × (x + 3)
Which gives;
(x - 6) × (x + 3) = x² + 3·x - 6·x - 18 = x² - 3·x - 18
Therefore, the factors of the expression, x² - 3·x - 18, are (x - 6) and (x + 3)
Midpoint formula: (x1+x2)/2, (y1+y2)/2
(1+5)/2 = 6/2 = 3 for x
(5+2)/2 = 7/2 = 3.5 for y
Midpoint: (3,3.5)
F(1)=6(1)+2
= 6+2
=8
g(f(1))= 2x/5 +4/5
= 2(8)/5 +4/5
= 16/5 +4/5
= 20/5
=4
Every line that does not have the slope of 2/7 is perpendicular to this line.
In order to find this fact, we first must find what is perpendicular. To do that, we first have to find the slope of this line. We can do this by solving for y.
7x + 2y = 3
2y = -7x + 3
y = -7/2x + 3/2
Now we can take the slope of -7/2 and flip and negate it. This will give us the perpendicular slope (2/7). Now we know any line that does not have this slope is not perpendicular to this line.
