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3 years ago

Question 1 (Multiple Choice Worth 1 points)

Mathematics

1 answer:

topjm [15]3 years ago

3 0

Answer:

-5

Step-by-step explanation:

we distribute the 3 and 2 on both sides to get:

3x+3=2x-2

we can subtract 3 on both sides to get

3x=2x-5

Now we subtract 2x on both sides to get

x=-5

Hope this helps :)

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What is the answer for <br><br><br> -|-10| + (-3) + |5|

Nuetrik [128]

Your answer would be -8

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3 years ago

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Write the exponential equation for this scenario. Georgiana invests $3000.00 in a CD. The CD earns 10% annual interest. How much

Dmitry_Shevchenko [17]

Answer:

The exponential equation is;

F = 30,000(1.01)^30

The value is;

$40,435.50

Step-by-step explanation:

Here, we are to write an exponential equation

Exponential equations generally take the form;

F = I(1 + r)^t

where F is the future value

I is the initial value

r is the growth percentage

t is the time

with respect to the question;

F = ?

I = 3,000

t = 30

r = 10% = 10/100 = 0.1

Writing the equation, we have

F = 30,000(1.+ 0.1)^30

F = 30,000(1.01)^30

F = $40,435.50

5 0

3 years ago

What is the security for the payment of a secured loan called

igomit [66]

The answer is C) collateral

8 0

4 years ago

Which of the following statements are the same? (A) x -= x + 4 (B) x = x + 4 - x (C) x = x - (x + 4) (A) and (B) are the same (A

Nesterboy [21]

Answer: (A) and (B) are the same

Step-by-step explanation:

for (A)

x-=x+4

x=x-(x+4)

x=x-x-4

x=4

for (B)

x=x+4-x

x=4

for (C)

x=x-(x+4)

x=x-x-4

x=-4

so (A) and (B) are the same because the value of their x is +4

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3 years ago

For what positive values of k does the function y=sin(kt) satisfy the differential equation y''+144y=0 ?

lina2011 [118]

Answer:

The positive value of k that the function y = sin(kt) satisfies the differential equation y'' + 144y = 0 is +12

Step-by-step explanation:

To determine the positive values of k that the function y = sin(kt) satisfy the differential equation y''+144y=0.

First, we will determine y''.

From y = sin(kt)

y' = $\frac{d}{dt}(y)$

y' = $\frac{d}{dt}(sin(kt))\\$

y' = kcos(kt)

Now for y''

y'' = $\frac{d}{dt}(y')$

y'' = $\frac{d}{dt}(kcos(kt))$

y'' = $-k^{2}sin(kt)$

Hence, the equation y'' + 144y = becomes

$-k^{2}sin(kt)$ + $144(sin(kt))$ $= 0$

$(144 - k^{2})(sin(kt)) = 0$

$(144 - k^{2})= 0$

∴ $k^{2} = 144\\$

$k =$ ± $\sqrt{144}\\$

$k =$ ± $12$

∴ $k = +12$ or $-12$

Hence, the positive value of k that the function y = sin(kt) satisfies the differential equation y'' + 144y = 0 is +12

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4 years ago