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labwork [276]
3 years ago
9

At the beginning of summer, Mark has $200 in savings and Ryan has $350. The brothers have mowing jobs set up for the summer. Bec

ause Mark is older, he receives $20 for each mowing job and Ryan receives $15. The brothers' parents pay for the fuel used to mow, so all of the money the brothers earn goes to savings. Write two equations, one for Mark and one for Ryan, to represent the money in savings (s) based on the number of mowing jobs (j) Mark and Ryan do. Determine the number of mowing jobs it takes for Mark to have the same amount in savings as Ryan does. Show your work.
Mathematics
1 answer:
zepelin [54]3 years ago
7 0

Answer:

m = 200 + 20j

r = 350 + 15j

Number of jobs is 30

<em></em>

Step-by-step explanation:

<u>Variable representation</u>

Let Mark's total earnings for moving be m

Let Ryan's total earnings for moving be r

Represent the number of jobs with j

<u>Setup equation</u>

Mark:

Initial\ Savings = 200

Rate = 20

So, the total savings is:

m = 200 + 20j

Ryan

Initial\ Savings = 350

Rate = 15

So, the total savings is:

r = 350 + 15j

<u>To get the number of jobs they save the same amount.</u>

We have:

m = r

Substitute values for m and r

200+20j = 350+15j

Collect Like Terms

20j - 15j = 350 - 200

5j = 150

Divide both sides by 5

j = \frac{150}{5}

j = 30

<em>Hence, the number of jobs is 30</em>

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3 years ago
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b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ e
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Answer:

Step-by-step explanation:

Hello!

<em>Full text</em>

<em>In a national survey college students were​ asked, "How often do you  wear a seat belt when riding in a car driven by someone​ else?" The response frequencies appear in the table to the right.​ (a) Construct a probability model for​ seat-belt use by a passenger.​ (b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ else? </em>

<em>Response , Frequency   </em>

<em>Never  102 </em>

<em>Rarely  319 </em>

<em>Sometimes  524 </em>

<em>Most of the time  1067 </em>

<em>Always  2727 </em>

n= 102+319+524+1067+2727= 4739

<em> ​(a) Complete the table below. </em>

<em>Response </em>

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<em>Never </em> P(N)= 102/4739= 0.0215

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Rarely </em> P(R)= 319/4739= 0.0673

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Sometimes </em> P(S)= 524/4739= 0.1106

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Most of the time  </em>P(M)= 1067/4739= 0.2252

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em>Always  </em>P(A)= 2727/4739= 0.5754

<em>​(Round to the nearest thousandth as​ needed.) </em>

<em />

<em>​(b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ else? </em>

<em>A. </em>

<em>​No, because there were 102  people in the survey who said they never wear their seat belt. </em> Incorrect, an event is considered unusual if its probability (relative frequency) is low, you cannot know if it is usual or unusual just by looking at the absolute frequency of it.

<em>B. </em>

<em>​Yes, because ​P(never) < 0.05. </em> Correct

<em> C. </em>

<em>​No, because the probability of an unusual event is 0.    </em>Incorrect, the probability of unusual events is low, impossible events are the ones with probability zero

<em>D. </em>

<em>​Yes, because 0.01 < ​P(never) <  0.10. </em>Incorrect, by the definition an event is considered unusual when its probability is equal or less than 5%.

I hope this helps!

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Answer:15

Step-by-step explanation:

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