Answer:
![m = 200 + 20j](https://tex.z-dn.net/?f=m%20%3D%20200%20%2B%2020j)
![r = 350 + 15j](https://tex.z-dn.net/?f=r%20%3D%20350%20%2B%2015j)
Number of jobs is 30
<em></em>
Step-by-step explanation:
<u>Variable representation</u>
Let Mark's total earnings for moving be m
Let Ryan's total earnings for moving be r
Represent the number of jobs with j
<u>Setup equation</u>
Mark:
![Initial\ Savings = 200](https://tex.z-dn.net/?f=Initial%5C%20Savings%20%3D%20200)
![Rate = 20](https://tex.z-dn.net/?f=Rate%20%3D%2020)
So, the total savings is:
![m = 200 + 20j](https://tex.z-dn.net/?f=m%20%3D%20200%20%2B%2020j)
Ryan
![Initial\ Savings = 350](https://tex.z-dn.net/?f=Initial%5C%20Savings%20%3D%20350)
![Rate = 15](https://tex.z-dn.net/?f=Rate%20%3D%2015)
So, the total savings is:
![r = 350 + 15j](https://tex.z-dn.net/?f=r%20%3D%20350%20%2B%2015j)
<u>To get the number of jobs they save the same amount.</u>
We have:
![m = r](https://tex.z-dn.net/?f=m%20%3D%20r)
Substitute values for m and r
![200+20j = 350+15j](https://tex.z-dn.net/?f=200%2B20j%20%3D%20350%2B15j)
Collect Like Terms
![20j - 15j = 350 - 200](https://tex.z-dn.net/?f=20j%20-%2015j%20%3D%20350%20-%20200)
![5j = 150](https://tex.z-dn.net/?f=5j%20%3D%20150)
Divide both sides by 5
![j = \frac{150}{5}](https://tex.z-dn.net/?f=j%20%3D%20%5Cfrac%7B150%7D%7B5%7D)
![j = 30](https://tex.z-dn.net/?f=j%20%3D%2030)
<em>Hence, the number of jobs is 30</em>