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3 years ago

What is the height of a triangular prism that has a height of 9 meters and a base with the following deminsions 4m 14m

Mathematics

1 answer:

Andrew [12]3 years ago

6 0

Answer:

252m^3

Step-by-step explanation:

A solid having a triangular base is what we call a triangular prism. For every prism, its volume is always equal to the area of its base times its height. In other words:

V = AxH

V - volume

A- area

H - height of prism

We know that:

h = 4 m (side of base)

b = 14 (other base side)

A = bh/2 = 14x4/2 = 28 m^2

And then: V = A x H = 28 x 9 = 252 m^3

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Using the number line below, draw a box and whisker plot for the following data: 12,18,18,20,22,22,25,26,30,30,32,32,35,35,38,49

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

Population size: 17

Median: 30

Minimum: 12

Maximum: 49

First quartile: 21

Third quartile: 35

Interquartile Range: 14

Outliers: none

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3 years ago

2. Stephanie has a bag of candy with 2 snickers, 3 butterfingers, 2 Reese's, and 3 Milky Ways bars. What is the probability that

PtichkaEL [24]

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Step-by-step explanation:

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2 years ago

What is the growth or decay and the percentage rate of Y=23(0.292)^x

torisob [31]

Answer:

So the decay percentage rate is of 70.8%

Step-by-step explanation:

An exponentil function has the following format:

$y = ca^{x}$

In which c is a constant.

If a>1, we have that a = 1 + r and r is the growth rate.

If a<1, we have that a = 1 - r and r is the decay rate.

In this problem:

a = 0.292

A is lesser than 1, so r is the decay rate.

1 - r = 0.292

r = 1 - 0.292

r = 0.708

So the decay percentage rate is of 70.8%

5 0

3 years ago

If ORBIT is coded BEOVG, then how is PLANET coded? /

arlik [135]

Answer:

1. CYNARG

Step-by-step explanation:

This a example of Caesar's Cipher, in which each letter in the original word leads to a ciphered letter according to the following equation:

$C = (P + o) \text{mod} 26$

In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.

Finding the offset:

O is coded B

O is the 15th letter in the alphabet, so $P = 15$ .

B is the 2nd letter in the alphabet, so $C = 2$

$C = (P + o) \text{mod} 26$

$2 = (15 + o) \text{mod} 26$

$|o = |2-15| \text{mod} 26$

$o = 13$

$C = (P + 13) \text{mod} 26$

PLANET:

P is the 16th letter in the alphabet.

$C = (16 + 13) \text{mod} 26 = 3$

So P is coded C.

L is the 12th letter in the alphabet:

$C = (12 + 13) \text{mod} 26 = 25$

L is coded Y(25th letter in the alphabet)

A is the 1st letter in the alphabet

$C = (1 + 13) \text{mod} 26 = 14$

A is coded N

N is the 14th letter in the alphabet

$C = (14 + 13) \text{mod} 26 = 1$

N is coded A

E is the 5th letter in the alphabet

$C = (5 + 13) \text{mod} 26 = 18$

E is coded R

So the correct answer is:

1. CYNARG

4 0

3 years ago

Which property is used in the statement? <br> If z=3+1, then 3+1=z

saul85 [17]

This is the symmetric property of equality, and in a more general form it can be written as: if a=b then b=a.

This is not to be confused with communicative property, which says that the order doesn't matter in some operations, such as addition, and can be written as a+b=b+a

6 0

3 years ago