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Ad libitum [116K]
2 years ago
15

Can there technically be a square root of 0 in mathematics or is that not allowed?

Mathematics
2 answers:
wolverine [178]2 years ago
5 0

Answer:

I think that technically since it is 0, that there can't be a square root of it because you can't ad anything to it, subtract from it, multiply by it, or divide by it.

Step-by-step explanation:

sdas [7]2 years ago
5 0

Answer:

yes

Step-by-step explanation:

it could be true the 0=1 so if you have 7 squared it would be 49 but if you have 7 0 it would be seven

:) Hope this helped have a good day! <3

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1 and 2 are a linear pair, and 2 and 3 are vertical angles. m 2=(5+4 y) and m 3=(6 y-25). what is m 1
poizon [28]
Vertical angles are equal to each other:
        ∠2     =    ∠3
     5 + 4y = 6y - 25
 →      30 = 2y
→       15 = y

∠2 = 5 + 4y = 5 + 4(15) = 5 + 60 = 65

linear pairs equal 180:
     ∠1 + ∠2 = 180
→ ∠1 + 65 = 180
→      ∠1    = 115

5 0
2 years ago
What is the solution to the equation 4x-6=10x-3?<br> x = -2<br> x=-1/2<br> x=1/2<br> x=2
kaheart [24]

Answer:

x= -1/2

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The volume of a CONE-shaped hole is 75pi ft cubed. If the hole is 9 feet deep, what is the radius of the hole?
Arturiano [62]

Answer:

The radius of hole is 5 feet

Step-by-step explanation:

Depth of conical hole = 9 feet

Let the radius of hole be r

Volume of conical hole =\frac{1}{3} \pi r^2 h

So, Volume of conical hole =\frac{1}{3} \pi \times r^2 \times 9

We are given that volume of a CONE-shaped hole is 75pi ft cubed.

So,\frac{1}{3} \pi \times r^2 \times 9=75 \pi

\frac{1}{3} \times r^2 \times 9=75

r^2=\frac{75 \times 3}{9}

r=\sqrt{\frac{75 \times 3}{9}}

r=5

Hence The radius of hole is 5 feet

6 0
3 years ago
France can complete 91 oil changes in 7 days how may oil changes can frances complete in 7 days
arsen [322]
Let oil change be x
91 / 7 = x / 11
(91 * 11) / 7 = x
13 * 11 = x
<span>143 = x Ans</span>
8 0
3 years ago
Evaluate f(x) = 2|x – 5| for f(–5) and f(0).
Elanso [62]

Answer:

f(–5) = 20, f(0) = 10

Step-by-step explanation:

f(-5):

f(-5) = 2|-5 -5|

f(-5) = 2|-10|

f(-5) = 2(10)

f(-5) = 20

f(0):

f(0) = 2|0 - 5|

f(0) = 2|-5|

f(0) = 2(5)

f(0) = 10

7 0
2 years ago
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