(a^3 - 2a + 5) - (4a^3 - 5a^2 + a - 2)
=a^3 - 2a + 5 - 4a^3 + 5a^2 - a + 2
= -3a^3 + 5a^2 - 3a + 7
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
376 because 276 + 100 is 376
Area of room: 7 x 6.5 = 45.5 sq. M.
Area of rug: 22/7 x 1.75^2 = 9.625 sq. M.
Area of loot not covered: 45.5 - 9.625 = 35.875 sq. M. ( round answer if needed)
Answer:
The sample space S for a probability model is the set of all possible outcomes.
