Answer: $187 will be in the account after 6 years.
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $100
r = 11% = 11/100 = 0.11
n = 1 because it was compounded once in a year.
t = 6 years
Therefore,.
A = 100(1 + 0.11/1)^1 × 6
A = 100(1 + 0.11)^6
A = 100(1.11)^6
A = $187
Answer:
-24
Step-by-step explanation:
-4-8= -12
8-2=6
12+6=18
-12b+6c+18
Greatest common factor = 6
-12/6=-2
6/6=1
18/6=3
D 6(-2b+1c+3)
-12(2)+6(-3)+18
-24+(-18)+18
-42+18= -24
-24
The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0
- Change in weight per day of hibernation = - 0.03
- Change in weight for 115 days = - 3.45 ounces
A linear model can be created using the data in the table given using a regression calculator or excel ;
The linear model obtained in the form y = m + bx is :
- y = - 0.03x + 0
- y = change in weight
- x = number of days of hibernation
- Intercept = 0
- Slope = -0.03
- The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.
- Using the regression equation, substitute, the vlaue of x = 115
- -0.03(115) + 0 = - 3.45
Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.
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Answer:
1. 8.3%
Step-by-step explanation:
Relative error = absolute error/expected measurement
The expected measurement is given as 6 ft.
Now, the absolute error is usually equal to half of a unit of the measure.
This means the absolute error in this case is ½ × 1 = 0.5 ft
Thus, the exact measurement will be;
6 ± 0.5
Thus;
Relative error = 0.5/6
Relative error = 0.083
Expressing it in percentage gives 8.3%