Answer:
k=0
Step-by-step explanation:
Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
i'm 75% sure the answer is C hope this helps
3p+2h=195
p + 15 = h
3p + 2(p + 15) = 195
3p + 2p + 30 = 195
5p = 165 (combine like terms and isolate your variable)
p = 33
33 + 15 = 48 (plug 33 into your original second equation)
ANSWER: 33 pretzels and 48 hotdogs
**You can plug these into your original (first) equation to check your answer
