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3 years ago

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Mathematics

1 answer:

Andrei [34K]3 years ago

7 0

Answer:

Circle 1=6x+2y

Rectangle 4 = 3x+y

Circle 4 = 5x

Step-by-step explanation:

4x+3y and 2x-y can be added to find result for the circle.

Let C1 represent circle 1

4x+3y+2x-y=C1\\

Combining\:like\:terms\\

4x+2x+3y-y=C1

6x+2y=C1

So, The result is: C1=6x+2y

Now, We need to solve:

Let R1 represent rectangle 4

x+4y + R1 = 4x+5y

R1=4x+5y-(x+4y)

R1=4x+5y-x-4y

R1=4x-x+5y-4y

R1=3x+y

So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y

Now, We need to solve the equation:

Let C4= Circle 4

2x-y+3x+y=C4

Combining the like terms

2x+3x-y+y=C4

5x=C4

So, Solving 2x-y+3x+y=C4 we get C4 = 5x

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If the subtrahend is 9 and the difference is 8 what is the minuend

enyata [817]

The subtrahend is 9 and the difference is 8 and the minuend is 17

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3 years ago

Fiona’s Number:

Amanda [17]

Answer:

He should dial 289-743-1560

Step-by-step explanation:

The first three digits: "My first three digits are the square of an integer less than twenty"

Step 1: We can get the first three by looking at the squares of the integers from 1 to 19. We need a three digit number, so starting with 10, since 10² = 100, we list the squares of the integers from 10 to 19

10² = 100

11² = 121

12² = 144

13² = 169

14² = 196

15² = 225

16² = 256

17² = 289

18² = 324

19² = 361

Step 2: "The first three digits are in ascending order" and no digits can repeat, so we eliminate the answers above that don't satisfy both of these condintions. This leaves just 3 choices:

13² = 169

16² = 256

17² = 289

*We will come back to this once we have more information.

The last 2 numbers: "the last two digits are multiples of sixty".

The only 2 digit number that is a multiple of 60 is 60, so 6 and 0 are the last 2 digits. This rules out two answers from Step 1 since no digits can repeat. Only 289 works since 169 and 256 each have a 6 in them. So now we know the first 3, and last 2 numbers!

2 8 9 _ _ _ _ _ 6 0

The last 4 numbers: "the last 4 digits are multiples of sixty"

We want to find a 4 four digit number that has 60 as the last 2 digits. Notice a pattern when you multiply 60 by certain digits...

60 x 1 = 60

60 x 2 = 120

...

60 x 6 = 360

60 x 11 = 660

60 x 16 = 960 (these all don't work since they are not 4 digits)

60 x 21 = 1260 (this is the first 4 digit result, but it doesn't work because

there is a '2' in it, and 2 has already been used as the

first digit of the number)

60 x 26 = 1560 (this number could work, so lets try it and see if we can

satisfy the rest of the statements)

Now our number is

2 8 9 _ _ _ 1 5 6 0

The second three digits: "The second three digits are in descending order" and "The sum of the second three digits is 14"

If we assume that 1, 5, 6 and 0 are the last four digits, we know that 2, 8 and 9 are the first three digits, this leaves 3, 4 and 7 as the three remaining digits.

3 + 4 + 7 = 14 so that condition is satisfied. We just need to write then in descending order, so our final number is

289-743-1560

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3 years ago

Read 2 more answers

F(x+h) = (x+h)² + 3(x+h)^3 How would I distribute this?

Leno4ka [110]

Answer:

f(x + h) = 3x³ + x² + 9h²x + 3h³ + h² + 9hx² + 2hx

General Formulas and Concepts:

Order of Operations: BPEMDAS
Distributive Property
Expand by FOIL (First Outside Inside Last)
Combining like terms

Step-by-step explanation:

Step 1: Define function

f(x) = x² + 3x³

f(x + h) is x = x + h

Step 2: Simplify

Substitute: f(x + h) = (x + h)² + 3(x + h)³
Expand by FOILing: f(x + h) = (x² + 2hx + h²) + 3(x + h)³
Rewrite: f(x + h) = (x² + 2hx + h²) + 3(x + h)²(x + h)
Expand by FOILing: f(x + h) = (x²+2hx+h²) + 3(x² + 2hx + h²)(x+h)
Distribute/Expand: f(x + h) = (x²+2hx+h²) + 3(x³+3hx²+3h²x+h³)
Distribute 3: f(x + h) = (x²+2hx+h²)+(3x³+9hx²+9h²x+3h³)
Combine like terms: f(x + h) = 3x³+x²+9h²x+3h³+h²+9hx²+2hx

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2 years ago

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1 is yes and 2 is no epa

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Write an equation that expresses the following relationship. p varies directly with d and inversely with the square root of u In

NARA [144]

The equation given as p varies directly with d and inversely with the square root of u is written as:

p = k1d
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and p = k2 $\frac{1}{ \sqrt{u} }$
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Thus,
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where K = K1*K2, K is the proportionality constant.

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3 years ago