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vovangra [49]
3 years ago
10

The cost of parking in a garage, in dollars, can be modeled by a step function whose graph is shown. How much does it cost to pa

rk for 3 hours and 45 minutes?
$3
$4
$6
$10

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0

Answer:

the cost is \$6

Step-by-step explanation:

observing the graph

we know that

For the interval of x------> (0,1] -----> the cost is \$0

For the interval of x------> (1,3] -----> the cost is \$4

For the interval of x------> (3,4] -----> the cost is \$6

For the interval of x------> (4,infinite) -----> the cost is \$10

In this problem we have

3 hours and 45 minutes

therefore

the value of x belong to the interval (3,4]

the cost is \$6

vagabundo [1.1K]3 years ago
6 0
3 hours 45 minutes=3 hours (45 minutes)(1 hour)/(60 minutes)
3 hours 45 minutes=3 hours 0.75 hours
3 hours 45 minutes = 3.75 hours
3 hours < 3.75 hours < 4 hours →Cost=$6

Answer: Third option $6
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Read 2 more answers
Evaluate the following expressions, and justify your answers.<br> WhatPower7(49)
MaRussiya [10]

Answer:

whatpower7(49) = 2

Step-by-step explanation:

given data  

WhatPower7(49)

to find out

Evaluate the expressions WhatPower7(49)

solution

as we know that whatpower mean exponent of equation so we get by given equation  

we know whatpower7(49) = 2

because  

we know that  7 × 7 = 49  

so that 7² = 49

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Element X is a radioactive isotope such that every 51 years, its mass decreases by half. Given that the initial mass of a sample
pychu [463]

Answer: It will take 6 years for 7500 grams of X to reach 6900 grams.

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  

a - x = amount left after decay process  

a) for completion of half life:  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

51=\frac{0.69}{k}

k=\frac{0.69}{51}=0.0135years^{-1}

b) for  7500 g to reach to 6900 g

t=\frac{2.303}{0.0135}\log\frac{7500}{6900}

t=6years

It will take 6 years for 7500 grams of X to reach 6900 grams.

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