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Yuki888 [10]
3 years ago
5

Consider the barn shown below. Assume that the barn has no floor. Part A: What is the volume of the barn?Part B: What is the sur

face area of the barn?
Offering 20 brain pts!!!
Mathematics
1 answer:
mafiozo [28]3 years ago
6 0

Answer:

the volume is Pie X Y^-3= 6 + 7/2 which means the surface area is half of Pie/12

Step-by-step explanation:

i don't know there's no picture

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Explain how to calculate the radius of a<br> circle if you know its diameter.
Marianna [84]

Answer:

r=d÷2 is the right answer

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Which pair of triangles can be proven congruent by SAS?
kap26 [50]

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i don't know

Step-by-step explanation:

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10 months ago
Sarah buys a shirt on sale at Jersey's. The original price was $28, but the shirt is on sale for 30% off. If there is a 5% sale
Helga [31]

Answer:

$20.58

Step-by-step explanation:

28 x 0.30 = 8.4

28 - 8.4 = 19.6

19.6 x 0.05 = 0.98

19.6 + 0.98 = 20.58

4 0
2 years ago
Which expression is equivalent to <img src="https://tex.z-dn.net/?f=%20-3%5E%7B-4%7D%20" id="TexFormula1" title=" -3^{-4} " alt=
galben [10]
I'm back lol

-3^(-4) = -(1/3)^4 = -1/81
5 0
2 years ago
Read 2 more answers
Determine the longest interval in which the given initial value problem is certain to have a unique twice-differentiable solutio
AnnZ [28]

Answer:

y'' + \frac{7}{t} y = 1

For this case we can use the theorem of Existence and uniqueness that says:

Let p(t) , q(t) and g(t) be continuous on [a,b] then the differential equation given by:

y''+ p(t) y' +q(t) y = g(t) , y(t_o) =y_o, y'(t_o) = y'_o

has unique solution defined for all t in [a,b]

If we apply this to our equation we have that p(t) =0 and q(t) = \frac{7}{t} and g(t) =1

We see that q(t) is not defined at t =0, so the largest interval containing 1 on which p,q and g are defined and continuous is given by (0, \infty)

And by the theorem explained before we ensure the existence and uniqueness on this interval of a solution (unique) who satisfy the conditions required.

Step-by-step explanation:

For this case we have the following differential equation given:

t y'' + 7y = t

With the conditions y(1)= 1 and y'(1) = 7

The frist step on this case is divide both sides of the differential equation by t and we got:

y'' + \frac{7}{t} y = 1

For this case we can use the theorem of Existence and uniqueness that says:

Let p(t) , q(t) and g(t) be continuous on [a,b] then the differential equation given by:

y''+ p(t) y' +q(t) y = g(t) , y(t_o) =y_o, y'(t_o) = y'_o

has unique solution defined for all t in [a,b]

If we apply this to our equation we have that p(t) =0 and q(t) = \frac{7}{t} and g(t) =1

We see that q(t) is not defined at t =0, so the largest interval containing 1 on which p,q and g are defined and continuous is given by (0, \infty)

And by the theorem explained before we ensure the existence and uniqueness on this interval of a solution (unique) who satisfy the conditions required.

7 0
3 years ago
Read 2 more answers
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