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Yuki888 [10]
3 years ago
5

Consider the barn shown below. Assume that the barn has no floor. Part A: What is the volume of the barn?Part B: What is the sur

face area of the barn?
Offering 20 brain pts!!!
Mathematics
1 answer:
mafiozo [28]3 years ago
6 0

Answer:

the volume is Pie X Y^-3= 6 + 7/2 which means the surface area is half of Pie/12

Step-by-step explanation:

i don't know there's no picture

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What is twice the number of n and 11
saul85 [17]

Answer:

2n+22

Step-by-step explanation:

(n+11)2=

2n+22

7 0
3 years ago
I really need help:)))
vovikov84 [41]

Answer:

0.985

Step-by-step explanation:

You can do 1 - 0.015 to solve this problem.

1 - 0.015 = 0.985

Hope that helps!

7 0
3 years ago
Read 2 more answers
A piece of a chain's length and weight are in proportion. If 320 cm of chain weighs 8 kg, then
Dafna11 [192]

Answer:

B. 80 cm of chain weighs 2 kg.

Step-by-step explanation:

In order to choose the correct answer, we need to define the comparative relation between the length and weight of the chain. We will do this by performing the simple operation of division.

It is easier to divide the larger number by the smaller and that is what we will show here (although <em>you can do as you wish and still get the same result</em> - it's math!):

320 ÷ 8 = 40

The result we got is 40. This means that <u>the length of the chain is equal to the value of forty of its weights!</u> And this will be the operation we will perform in order to determine the right answer:

A) Does 2 (kg) multiplied by 40 equal 40 (cm)? No, therefore, it is incorrect.

B) Does 2 (kg) multiplied by 40 equal 80 (cm)? <u>Yes, this answer is correct!</u>

Just in case, we will perform this action with the rest of the possible choices:

C) 4 kg × 40 = 160 and NOT 80 cm.

D) 2 kg × 40 = 80 and NOT 160 cm.

5 0
3 years ago
A flagpole has a height of 10 yards. It will be supported by 3 cables, each of which is attached to the flagpole at a point 4 ya
Contact [7]
Pytagorean theorem

height10
attached at 10-4=6 yards from bottom
8 yards from base to away


a^2+b^2=c^2
a and b are side legnths and c=hypotonuse
so therfore we are given a and b and we must solve for c


so
6=height
8=base

6^2+8^2=c^2
36+64=c^2
100=c^2
square root
10=c

so therfor the legnth of each cable is 10 yards
3 cables so 3 times 10=30

30 yards needed

7 0
3 years ago
Help find y .. slope is m=-5/8
goblinko [34]

y = 8

using the ' gradient formula' m = (y₂ - y₁)/(x₂ - x₁)

with (x₁, y₁) = (3, 3), (x₂, y₂) = (- 5, y) and m = - \frac{5}{8}

(y - 3)/( - 5 - 3) = - \frac{5}{8}

(y - 3)/(-8) = - \frac{5}{8}

multiply both sides by - 8 to eliminate fractions

y - 3 = 5

add 3 to both sides

y = 5 + 3 =8


5 0
3 years ago
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