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3 years ago

5

Consider the barn shown below. Assume that the barn has no floor. Part A: What is the volume of the barn?Part B: What is the sur

face area of the barn?
Offering 20 brain pts!!!

1 answer:

mafiozo [28]3 years ago

6 0

Answer:

the volume is Pie X Y^-3= 6 + 7/2 which means the surface area is half of Pie/12

Step-by-step explanation:

i don't know there's no picture

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Angelina_Jolie [31]

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3 years ago

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

so

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

so

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

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therefore

The original length was 41 inches and the original width was 16 inches

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3 years ago

Solve algebraically for x

Anton [14]

3x + 1 = (x-1)^2
3x + 1 = x^2 - 2x + 1
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x = 0,5

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3 years ago

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katen-ka-za [31]

Hello there!

The answer is:
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3 years ago