Answer: C) 163
Step-by-Step Solution:
In the Right Triangle formed to the extreme right, lets mark the angles as
∠1, ∠2 and ∠3.
Therefore, from the Figure :-
∠1 = 73°
∠2 = 90°
By Angle Sum Property :-
∠3 = 180 - (73 + 90)
∠3 = 180 - 163
=> ∠3 = 17°
The Angle which forms a Linear Pair with ∠3 is the Corresponding Angle of ∠r, and Corresponding Angles are Equal.
Therefore,
=> 180 - ∠3
= 180 - 17
=> 163°
Therefore, the Angle that forms the Linear Pair with ∠3 is 163°
This Angle is Corresponding to ∠r and hence they are Equal ie. ∠r = 163°
Hence, ∠r = 163°
Answer:
C) 1/3
Step-by-step explanation:
First look at equation: 3x+y=1
re-write as y=mx+b
y=-3x+1
so the slope of this equation i s-3
so if a line is perpendicular to the above equation,
its slope will be reciprocal negative which is 1/3
Answer:
Step-by-step explanation:
Because CB = 6 cm, we can find CD
Use Triangle CDB.
<BCD = <BCA - <ACD
<BCD = ?
<BCA = 90
<ACD = 60
<BCD = 90 - 60
<BCD = 30
Cos 30 = CD / CB
CD = Cos(30) * BC
CD = 5.196 cm
<A = 90 - ACD
<ACD = 60
<A = 90 - 60
<A = 30
Sin(<A) = CB / AB
AB = CB / sin(<A)
AB = 6 / 0.5
AB = 12
Area =1/2 CD * AB
Area = 1/2 * 5.196 * 12
Area = 31.18
-4/2=-2
(-2)^2=4
the blank is +4
x^2-4x+4
factored
(x-2)^2
Answer:
4/7
Step-by-step explanation:
