The expected value of the discrete distribution, if you have to pay $.50 to pick one package at random, is of -$0.08.
<h3>What is the mean of a discrete distribution?</h3>
The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.
For this problem, considering the cost of $0.5, the distribution is given as follows:
- P(X = 0.2) = 12/(12 + 15 + 23) = 12/50 = 0.24.
- P(X = -0.1) = 15/(12 + 15 + 23) = 15/50 = 0.3.
- P(X = -0.2) = 23/(12 + 15 + 23) = 23/50 = 0.46.
Hence the expected value is given by:
E(X) = 0.2 x 0.24 - 0.3 x 0.1 - 0.2 x 0.46 = -$0.08.
More can be learned about the expected value of a discrete distribution at brainly.com/question/13008984
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Answer:
hello thereeeee
ans is 23.5
Step-by-step explanation:
so lets start
first of all remove decimal of divisor 1.1/25.85 multiplying by 10
11/258.5
now first multiply by 2
now we get 22 and subtract with 25 => 25-22 = 3
so left is
38
now 11*3 = 33
so now by 3
38-33= 5
bringing another 5 down
we get 55
now quotient is 23. something ( as we bought .5 down)
and now 11*5 = 55
so
23.5 is answer
Answer:
AE =15
Step-by-step explanation:
BC=16-12 = 4
AE=x
12/4 = x/5
Cross multiplication
4x=60
x=15
4x3 = 12
5x3 =15
1.65 rounded to the nearest whole number is 2
