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serg [7]
3 years ago
8

Find the percent of decrease from 6 to 5.

Mathematics
1 answer:
lozanna [386]3 years ago
3 0

Answer:

Use this

Step-by-step explanation:

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Sasha spent $7.00 of the $20.00 in her wallet. Which decimal represents the fraction of the $20.00 Sasha spent?
gregori [183]

Answer:

0.7

Step-by-step explanation:

7 0
2 years ago
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Simplify the expression 18x^2/3x^6 .
sammy [17]

Answer:

6/x^4

Step-by-step explanation:

7 0
2 years ago
Of the 8 students in the chess club, three will represent the club at an upcoming competition. How many different 3-person teams
xz_007 [3.2K]
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have

C(8,3) = 8!/(8-3)!3!
C(8,3) = 56

There are 56 3-person teams that can be formed from the 8 students. 
6 0
2 years ago
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A plane flying horizontally at an altitude of 1 mile and a speed of 510 mi/h passes directly over a radar station. Find the rate
sdas [7]

Answer:

442 miles

Step-by-step explanation:

Given

To properly solve this question, I illustrate some given parameters using attached image

From the image, apply Pythagoras theorem

x^2 + 1^2 = y^2

Differentiate w.r.t time (t)

2x\frac{dx}{dt} + 0 = 2y\frac{dy}{dt}

2x\frac{dx}{dt} = 2y\frac{dy}{dt}

Divide both sides by 2

x\frac{dx}{dt} = y\frac{dy}{dt}

From the question, we have that the plan travels are 510mi/h.

This implies that:

\frac{dx}{dt} = 510mi/h

So, we then calculate the value of x when the distance (y) is 2mi i.e.:

y = 2mi

Apply Pythagoras theorem

x^2 + 1^2 = y^2

x^2 + 1^2 = 2^2

x^2 + 1 = 4

x^2 = 4-1

x^2 = 3

x = \sqrt 3

So, the expression becomes:

x\frac{dx}{dt} = y\frac{dy}{dt}

\sqrt 3 * 510 = 2* \frac{dy}{dt}

\frac{\sqrt 3 * 510}{2} =  \frac{dy}{dt}

\sqrt 3 * 255 =  \frac{dy}{dt}

\frac{dy}{dt} = 255\sqrt 3

\frac{dy}{dt} = 255 * 1.7321

\frac{dy}{dt} = 441.655

\frac{dy}{dt} = 442

<em>Hence, the distance is 442 miles</em>

7 0
2 years ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
2 years ago
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