A polynomial p has zeros when x = -2, x = 1/3, and x =3.
1 answer:
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Answer:
8. 4 +2q²/p² -4r/p +r²/p²
9. (x, y) = (3/4, -17/8)
Step-by-step explanation:
All of these questions are asking you to make use of the fact that ...
α + β = -q/p
αβ = r/p
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8. (2 +α²)(2 +β²) = 4 + 2(α² +β²) +α²β²
= 4 +2((α+β)² -2αβ) +(αβ)²
Substituting the above for the sum and product, you have ...
= 4 + 2((-q/p)² -2(r/p)) +(r/p)²
= 4 +2q²/p² -4r/p +r²/p²
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9. This is asking for the vertex of the parabola. The x-coordinate is ...
x=-b/(2a) = -(-3)/(2(2) = 3/4
Then the y-coordinate is ...
y = (2(3/4) -3)(3/4) -1 = (-3/2)(3/4) -1 = -9/8 -1 = -17/8
The (x, y) values of interest are (3/4, -17/8).
Answer:
The x-axis
Step-by-step explanation:
The graph of the equation x=y2+4 is symmetric with respect to the x-axis.
To test for symmetry with respect to the x-axis we substitute -y in place of y and simplify the equation. If the resulting equation is identical to original one then the function is symmetric with respect to the x-axis;
which is identical to the original equation
