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MaRussiya [10]
3 years ago
8

A polynomial p has zeros when x = -2, x = 1/3, and x =3.

Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0

Answer:

p(x) = ( x +2) (3x - 1) ( x-3)

Step-by-step explanation:

We know the equation for a polynomial with given zeros is

f(x) = a(x-b1) (x-b2)...... where b are the zeros and a is a constant

Since the zeros are x = -2, x = 1/3, and x =3.

p(x) = a( x - -2) (x - 1/3) ( x-3)

p(x) = a( x +2) (x - 1/3) ( x-3)

We can pick the value of a since we are not given a point on the function.  Pick a=3

p(x) = 3( x +2) (x - 1/3) ( x-3)

Rewriting the second term

p(x) = ( x +2) (3x - 1) ( x-3)

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3 years ago
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Answer:

Step-by-step explanation:

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3 years ago
<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B3%7D%2B4%5Cright%29%5Cleft%281%2B%5Csqrt%7B3%7D%5Cright%29" id="TexFormula
kirza4 [7]

Answer:

\huge\boxed{\sf 7 + 5\sqrt{3} }

Step-by-step explanation:

(\sqrt{3} +4)(1+\sqrt{3})\\\\= \sqrt{3}(1+\sqrt{3} )+4(1+\sqrt{3})\\\\= \sqrt{3} + (\sqrt{3} )^2 + 4 + 4\sqrt{3} \\\\= \sqrt{3} + 3+4+4\sqrt{3}  \\\\= 7 + \sqrt{3}  + 4\sqrt{3} \\\\Take \ \sqrt{3} \ common\\\\= 7 + \sqrt{3} (1+4)\\\\= 7 + \sqrt{3}(5)\\\\= 7 + 5\sqrt{3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
2 years ago
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