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timurjin [86]
2 years ago
15

Help its for calculus

Mathematics
2 answers:
SashulF [63]2 years ago
7 0

Answer:

maybe its e(1/y)

Sedbober [7]2 years ago
6 0

Answer:

it should be e(1/y)

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Someone please help me I’ll give out brainliest please dont answer if you don’t know
sasho [114]

Answer:

$56.25

Step-by-step explanation:

3% of 750, then multiply by 2.5

6 0
3 years ago
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts
Damm [24]

Answer:

t=2.08 seconds.

Step-by-step explanation:

Well, in this example, H(t)=-0.6cos(2pi/2.5)t+1.5 should be equal to 1.2. If calculated, -0.6cos(0.8pi)t=1.2-1.5 which is equal to -0.6cos(0.8pi)t=-0.3, then cos(0.8pi)t=0.5. The value of cosine in terms of radians when it is equal to 0.5 is pi/3. So, cos(0.8pi)t=cos(pi/3). If simplified, (0.8pi)*t=5pi/3. pi's are cancelled out and t is calculated as 2.08333... If rounded to the nearest hundredth it is 2.08.

4 0
3 years ago
WILL MARK U AS BRAINLIEST SHOW WORK SOLVE BY ELIMINATION-3x+y=-18<br> -3x+y=-6
Sindrei [870]
No solution exists for -3x+y=-18 and -3x+y=-6
8 0
3 years ago
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
Please assist me with the trapezoid problems​
White raven [17]

Problem 4

a)

MR = AG is a true statement because MARG is an isosceles trapezoid. The diagonals of any isosceles trapezoid are always the same length.

-------------------------

b)

MA = GR is false. Parallel sides in a trapezoid are never congruent (otherwise you'll have a parallelogram).

-------------------------

c)

MR and AG do NOT bisect each other. The diagonals bisect each other only if you had a parallelogram.

=================================================

Problem 5

a)

LC = AJ (nonparallel sides of isosceles trapezoid are always the same length)

x^2 = 25

x = sqrt(25)

<h3>x = 5</h3>

-------------------------

b)

LU = 25

UC = 25 because point U cuts LC in half

LC = LU+UC = 25+25 = 50

AJ = LC = 50 (nonparallel sides of isosceles trapezoid are always the same length)

AS = (1/2)*AJ

AS = (1/2)*50

<h3>AS = 25</h3>

-------------------------

c)

angle LCA = 71

angle CAJ = 71 (base angles of isosceles trapezoid are always congruent)

(angleAJL)+(angleCAJ) = 180

(angleAJL)+(71) = 180

angle AJL = 180-71

<h3>angle AJL = 109 </h3>
5 0
3 years ago
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