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jasenka [17]
3 years ago
8

Solve application problems using radical equations. How far from the base of the house do you need to place a 13-foot ladder so

that it exactly reaches the top of a 10- foot tall wall?
Mathematics
1 answer:
Pavel [41]3 years ago
4 0
C^2 = a^2 +b^2
a^2 = c^2 - b^2
a^2 = 13^2 - 10^2
a^2 = 69
a = root69

Therefore you need to put the ladder approximately 8.3 feet from the base of the house.
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Please answer this question, 30 points and will give brainliest!
kotykmax [81]

Answer:

∠C = 80 ° ; ∠ T = 40°.

Step-by-step explanation:

Triangle CRS is isosceles because it has two sides of equal length. (CR and CS are radii).

An isosceles triangle has also two equal angles, which means that ∠CRS= ∠CSR.

Therefore, ∠C = 80 ° (180° – 50° - 50°)  because the sum of angles in a triangle is 180 degrees.  

∠C is the central angle of the arc RS.

∠ T is the inscribed angle of the arc RS.

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6 0
3 years ago
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Lady bird [3.3K]

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Read 2 more answers
The part of a parallelogram is 240 cm ^2 and the height is 20 cm. Find the corresponding base.
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240 = base * 20
base = 240 / 20
base = 12 cm


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3 years ago
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